A rocket launched from the ground rises vertically with an acceleration of 30 m/s/s for 9.1 s until its motor stops. The acceleration of gravity is 9.8 m/s/s. Disregarding air resistance, what maximum height above the ground will the rocket achieve? Answer is units of km.
v = v(initial) + at
x = x(initial) + v(initial)t + (1/2)at^2
The Attempt at a Solution
h = x - x(initial)
h = (1/2)(30)(9.1)^2
h = 1242 m
h = 1.242 km
I also tried it another way and got the same result. I don't see what could possibly be wrong.