- #1

- 523

- 0

I saw this explained somewhere by the fact that since the charge operator is

[itex]Q = \left(

\begin{matrix}

0 & 0 \\

0 & -1

\end{matrix}

\right)[/itex],

it does not commute with any of the Pauli matrices. Can anyone explain where this definition of the charge operator comes from? I'm failing to understand even what the charge operator is.