Movable mirror of a Michelson interferometer

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SUMMARY

The discussion centers on calculating the displacement required for the movable mirror of a Michelson interferometer to produce 2000 fringes using a 589-nm light source. The key equation involves the relationship between the wavelength and the path length difference, where constructive interference occurs at integer multiples of the wavelength. Specifically, to achieve 2000 fringes, the path length difference must equal 2000 times the wavelength, resulting in a total displacement of 2000 * 589 nm, or 1.178 mm. Additionally, a question regarding the Sagnac interferometer's configuration and intensity reduction is raised, indicating a need for further analysis of light behavior in that setup.

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  • Understanding of Michelson interferometer principles
  • Knowledge of wavelength and path length difference in interference patterns
  • Familiarity with constructive interference concepts
  • Basic understanding of Sagnac interferometer configurations
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i know the question may be a bit stupid to some people, but i seriously don't know how to do it...

Homework Statement


How far must the movable mirror of a Michelson interferometer, illuminated by a 589-nm source, be displaces for 2000 fringes to move past the reference point?


Homework Equations



i have no idea

The Attempt at a Solution



i don't know how to solve it
 
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What's the path length difference associated with 2000 fringes?
 


ideasrule said:
What's the path length difference associated with 2000 fringes?

it does not say, that was the whole question.
 


Yes, but it does tell you the wavelength, and constructive interference occurs when the path length difference is an integer multiple of the wavelength.
 


can anyone answer this question
In Sagnac interferometer replace the beam splitter by a fourth mirror and calculate how many loops around the interferometer can the light make before its intensity is reduced by 99%??
 

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