Moving a 250kg Elephant with 425N Force

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Homework Help Overview

The problem involves calculating the coefficient of kinetic friction for a scenario where a boy exerts a horizontal force on a 250kg elephant sliding on carpeting. The force applied is 425N.

Discussion Character

  • Exploratory, Assumption checking

Approaches and Questions Raised

  • Participants discuss the relationship between the applied force and friction, with some attempting to derive the coefficient of kinetic friction using the formula involving normal force and maximum frictional force.

Discussion Status

There are various interpretations of the problem, particularly regarding the role of friction and the applied force. Some participants have provided calculations, while others are questioning the assumptions made about the forces involved.

Contextual Notes

Participants are navigating the definitions of forces at play, particularly the nature of friction in relation to the applied force and the normal force. There is a lack of clarity on why certain values are used in the calculations.

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Homework Statement


A boy puts a 250kg elephant on a piece of carpeting and slides it across the floor by exerting a horizontal force of 425N on the elephant



Homework Equations


Ff = uKFn


The Attempt at a Solution


Fn = Fg
Fnet = Fap - Ff
Fnet = 425 - Ff
ma = 425 - uKFn
250a = 425 - uK(2450)
 
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what is the question asking?
 
for coefficient of kinetic friction
 
mue=f max/fn
425N/(250x9.81)
mue=.173

I believe that's how you do it
 
why is friction 425N
 
its force
 

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