Which Force Application Minimizes Effort When Moving a Box?

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Homework Help Overview

The discussion revolves around determining the optimal force application method for moving a box at constant speed across a horizontal surface, considering the effects of friction and the angle of force application.

Discussion Character

  • Conceptual clarification, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • Participants explore different scenarios of applying force (pushing vs. pulling) and their impact on the normal force and friction. Questions arise regarding the differences in normal force when applying force at an angle versus horizontally.

Discussion Status

Several participants have offered insights into the equations governing friction and normal force. There is an ongoing exploration of how the direction of the applied force influences the overall force required to move the box. Some participants express uncertainty about their initial assumptions and interpretations of the problem.

Contextual Notes

Participants are navigating the implications of different force applications while adhering to the constraints of the problem, including the coefficient of kinetic friction and the requirement for constant speed. There is a noted confusion regarding the interpretation of the angles involved in the force application.

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Homework Statement


You want to apply a force on a box so that it moves with constant speed across a horizontal floor. The coefficient of kinetic friction between the box and the floor is u. Of the four following cases, the force you apply on the box will be smallest when you

a) Push on it with a force applied at an angle 0<X<90 downward from the horizontal;
b) pull on it with a force applied at the same angle X as in (a), upward from the horizontal;
c)do either (a) or (b) since the applied force is the same;
d)pull or push with a force applied horizontally


Homework Equations


Ff=Fa, to keep at a constant speed


The Attempt at a Solution


The correct answer is b but I have no idea why.
I chose c as my answer seeing that a and b would both result in the same thing, only that the weight of the box would concentrate in the front in situation (a) and that the weight would concentrate in the back in situation (b). I felt that this difference would not change the amount of force needed. Are there any other factors I have not considered? Thanks
 
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The friction can be calculated by F=uR, where R is the normal reaction force. Do you know how to find the normal reaction force? More specifically, how will it be different when the force applied is a pull compared to when it is a push?
 
The friction equation is Ff=u(mg-FasinX).
I actually have no idea why the force would be different pushing from one side or pulling from the another.
 
21385 said:
The friction equation is Ff=u(mg-FasinX).
That's for a pull. If you are pushing the box with a force downwards from the horizontal, you will be adding to the normal force, and thus the correct equation will be Ff=u(mg+FasinX).
 
Cristo, interesting. You're adding ergonomics to the eqn. But i see the wisdom, at arms length to pull relieves N force while pushing adds to it.
Cheers.
 
thanks, cristo
omg, i am so stupid, i thought choice a) was pushing from the angle below the horizontal
 
Last edited:

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