Sauk
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Homework Statement
Multipath dispersion of a pulse of light in an optical fiber.
How is this problem solved?
Multipath dispersion of a pulse of light in an optical fiber.
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Multipath dispersion of a pulse of light in an optical fiber.
How is this problem solved?
Discussion
Lucky13T
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Multipath dispersion is can be solved by:
1) Making the fibre (core) very narrow.
2) By making the cladding which surrounds the core very close to the core refractive index. The closer the two refractive indexes the better as any light that is less than a certain angle will be lost therefore only light that is at the right angle, preferably straight to the optical fibre, reaches the receiver.
1) Making the fibre (core) very narrow.
2) By making the cladding which surrounds the core very close to the core refractive index. The closer the two refractive indexes the better as any light that is less than a certain angle will be lost therefore only light that is at the right angle, preferably straight to the optical fibre, reaches the receiver.
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Why does making the core narrower reduce multipath dispersion?
MalachiK
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I've been thinking about this problem today, and I found this page as part of a search for more information.
At first I thought that it was obvious why reducing the width of the fibre would reduce the multipath dispersion. But having tried the problem with maths, I'm not so sure.
I've tried to calculate the maximum possible path difference along a fibre of length l and width d that has a maximim transmission angle of [tex]\theta[/tex] to the normal of the core cladding boundary. I've come up with an expression for this path difference in terms of the length of the fibre... <Attached are my scribbles>
The problem with this formulae is that the path difference becomes a larger fraction of the total length of the fibre as the width of the fibre gets smaller.
Can anyone tell me where my maths has gone wrong?
Thanks
At first I thought that it was obvious why reducing the width of the fibre would reduce the multipath dispersion. But having tried the problem with maths, I'm not so sure.
I've tried to calculate the maximum possible path difference along a fibre of length l and width d that has a maximim transmission angle of [tex]\theta[/tex] to the normal of the core cladding boundary. I've come up with an expression for this path difference in terms of the length of the fibre... <Attached are my scribbles>
The problem with this formulae is that the path difference becomes a larger fraction of the total length of the fibre as the width of the fibre gets smaller.
Can anyone tell me where my maths has gone wrong?
Thanks
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