Multiple lines in H2 and Hg emission spectra

Click For Summary
SUMMARY

The discussion focuses on the emission spectra of hydrogen (H2) and mercury (Hg), revealing that H2 exhibits three spectral lines while Hg shows five. The number of spectral lines is determined by the possible electron transitions between energy levels within the atoms. Specifically, the energy supplied to the atoms influences these transitions, which in turn dictate the emitted light's frequency based on the energy change during the transitions, as described by the formula f = E/h.

PREREQUISITES
  • Understanding of atomic energy levels
  • Familiarity with electron transitions
  • Knowledge of spectral analysis techniques
  • Basic grasp of the formula f = E/h
NEXT STEPS
  • Research the Rydberg formula for hydrogen emission spectra
  • Study the electron transition mechanisms in mercury
  • Explore the principles of spectrography and its applications
  • Learn about the relationship between energy levels and spectral lines in different elements
USEFUL FOR

Students and researchers in physics, particularly those studying atomic spectra, as well as educators looking to enhance their understanding of electron transitions and spectroscopic techniques.

hagopbul
Messages
397
Reaction score
45
I was doing a test about rydberg constants using H2 and Hg light spectrum

And in the spectrograph I found that H2 have three spectra and the Hg have 5 spectra
And I DON'T KNOW WHY H2 have 3 lines and Hg have 5 lines? (Scientifically).

I know it is the numbers of the electrons that determine the number of the spectrum lines but how exactly?
Can anyone help me please:cry::confused::bugeye:
 
Physics news on Phys.org
Well it is the number of possible transitions that determine the number of spectrum lines you will see, and also the energy supplied to the atoms. If for example we imagine an atom has 3 energy levels, then the possible electron transitions would be :

n3 => n1 5 J
n3 => n2 3 J
n2 => n1 2 J

These energy levels are not proper values i have just made them up for the example. I have noted next to them the energy difference between each pair of shells. So if we supply energy to the electrons in an atom they may be excited to say the n3 state then they have gained 5J of energy. Now the electron will dexcite at some random time and could make either the n3 to n2 transition which means it will emit light of energy 3J, or make the n3 to n1 transition and emit light of 5J. The frequency of light depends on the energy change in the transition.

f = E/h
 
Last edited:

Similar threads

  • · Replies 7 ·
Replies
7
Views
3K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 6 ·
Replies
6
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
Replies
8
Views
5K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 16 ·
Replies
16
Views
3K
  • · Replies 2 ·
Replies
2
Views
2K