# Multiplying/Dividing Rational Expressions(Playing with AlgebraII Fractions)

1. Feb 28, 2009

### SETHOSCOTT

1. The problem statement, all variables and given/known data
[(4x-4x2)/x2+2x-3] * [(x2+x-6)/4x]

2. Relevant equations

3. The attempt at a solution
I'm so lazy, though, I do all this stuff mentally, so... Oby-kaby.
I individualized all groups into smaller units(I don't know how to say that in algebrish), by dividing by least common factor.

[4x(-1)(x-1)]/[(x-1)(x+3)] * [(x+3)(x-2)]/4x

then I multiply numerators, and denominators,

[4x(-1)(x-1)(x+3)(x-2)]/[(x-1)(x+3)(4x)]

then I use numbers of similair values to kill each other, resulting in...

(-1)(x-2)

THEN I got done doing some stuff, I got -x+2, dunno if right. Trembling in fear of overdominating, atomic family junky, math commander. Don't drink and use PC's. Then I was concured, which is insanely close to conquered, then somebody got worried of me posting problems, with them cheating, supplementing the ase of cheating, which goes back to me typing the work, then this paragraph, which doesn't open a continuim in explanations. But leaves the same question, and a new one. Did he spell continuim right? WHAT?!?

Last edited: Feb 28, 2009
2. Feb 28, 2009

### The Bob

I concur.

The Bob

3. Feb 28, 2009

### HallsofIvy

Staff Emeritus
Well, we can't tell you whether or not you are right if you don't show us what you did!

4. Feb 28, 2009

### SETHOSCOTT

WHAT?!? Concured? I edited, mentor, hoorah!!!!

5. Feb 28, 2009

### SETHOSCOTT

Did I do it right?

6. Mar 1, 2009

Heller?

7. Mar 1, 2009

### The Bob

The workings out are right.

The Bob

8. Mar 1, 2009

### SETHOSCOTT

Sweet, muchas gracias, the bob.:!!)

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