Multiplying numbers from One set with another set

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Bob created two sets of integers, one with even numbers from 1 to 30 and another with odd numbers. He multiplied each number from the odd set with every number in the even set, resulting in a total of 225 products. The sum of these products, denoted as "S," was calculated to be 54,000. An alternative method to find S involves multiplying the sum of the odd integers by the sum of the even integers, leading to the same result. The discussion highlights the efficiency of using formulas for quicker calculations in such problems.
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Homework Statement



Bob makes two sets: one with all the even integers between 1 and 30 inclusive, and another with all the odd integers inclusive. He called the sets Q and R. He multiplied each number from Q with each number in R. Then he added the 225 products together and called the result "S". What number does S represent?

(A) 8,000 (B) 18,000 (C) 36,000 (D) 54,000 (E) 86,000

Homework Equations

The Attempt at a Solution



Set Q = {1, 3, 5, 7, 9, 11, 13, 15, 17, 19, 21, 23, 25, 27, 29}
Set R = {2, 4, 6, 8, 10, 12, 14, 16, 18, 20, 22, 24, 26, 28, 30}

I noticed if I took 1 from Q and multiplied with every number in R, I get multiples of 2 from 2 to 30
Likewise, if I took 3 from Q and multiplied with every number in R, I get multiples of 6 from 6 to 90 and so on.

# from Q Range Sum (Added first term and last term and multiplied by 7 and then added the middle #)
1 2 to 30 32 * 7 + 16 = 240
3 6 to 90 96 * 7 + 48 = 720
5 10 to 150 160 * 7 + 80 = 1200
7 14 to 210 224 * 7 + 112 = 1680
9 18 to 270 288 * 7 + 144 = 2160

I stopped here because I noticed the sums were odd multiples of 240.

So then I found the first term which is 240 and the last term which would be 240 * 29 = 6960. The middle # here would be 3600.

6960 + 240 = 7200. There are 7 pairs of 7200 and the left out middle number 3600, thus the sum would be 54,000.

I was wondering if there is a shorter or easier or alternative method of solving this problem.
 
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Yes. Multiply the sum of the odds by the sum of the evens. 225x240 = 54000.
 
And there is a formula you can use for those sums to make it even faster.
 

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