Multiplying Radicals: Solving Pre-Algebra Homework

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Homework Help Overview

The discussion revolves around a pre-algebra problem involving the multiplication of radicals, specifically the expression (8√6 + √5)(√6 + 9√5). Participants are exploring the steps taken to simplify this expression and the implications of the order of terms in the final result.

Discussion Character

  • Exploratory, Assumption checking

Approaches and Questions Raised

  • The original poster attempts to use the FOIL method for multiplying binomials and applies properties of radicals. They express confusion about the order of terms in the final answer and question why their answer was marked incorrect despite the commutative property of addition.

Discussion Status

Some participants have provided guidance regarding the grading of the answer, suggesting that the instructor may have specific expectations for the format of the answer. The original poster is encouraged to seek clarification from their instructor regarding the grading decision.

Contextual Notes

The original poster mentions a lack of partial credit and expresses uncertainty about their understanding of the problem, indicating a need for further clarification on the grading criteria.

Illuvitar
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Homework Statement



Hey guys/gals I have need a clarification on one particular pre-algebra problem dealing with multiplying radicals. I thought I knew the steps to solve it (properties of radicals and distribution property, etc) but I am having trouble with this particular problem.

(8√6 +√5)(√6+9√5)

The Attempt at a Solution



Okay so I used used FOIL as if I was multiplying two binomials together so

(8√6 *√6) + (8√6 * 9√5) and (√5 *√6) + (√5 *9√5)

1) 8√6 *√6= 48 because (√n*√n= n)
2) I proceeded to use the Distribution property so 8√6 * 9√5= 72√30
3) Repeating step two with inner term: √5*√6=√30
4) Lastly inner term x outer term:√5 *√5 = √25

Okay so after using the Distribution property the new equation looks like this:
48+72√30+√30+9 √25

5) now I take take the square root of √25 which is 5 and multiply it by 9:
...9√25 becomes 45

now the equation reads:
48+72√30+√30+45

6) Now I add like terms and this is the point where I am missing a step or have messed up in some way in the above steps. After combining like terms I get:

93+73√30

the correct answer is 73√30+93

I thought addition was commutative so I didn't think that the order mattered but why when I combine 48 & 45 the sum ends up on the end of the equation and why does the order matter if addition is commutative? I got this question wrong because of the order but I've looked at this problem for a while now and I don't understand why the correct answer is in the order it is in and why it matters.

Also I'm sorry this was a long post and elementary problem but I just don't understand any clues to lead me in the right direction would be much appreciated. Thanks in advance for reading this or replying to it. And I hope this is in the right format, apologies if it isnt.
 
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Illuvitar said:

Homework Statement



Hey guys/gals I have need a clarification on one particular pre-algebra problem dealing with multiplying radicals. I thought I knew the steps to solve it (properties of radicals and distribution property, etc) but I am having trouble with this particular problem.

(8√6 +√5)(√6+9√5)

The Attempt at a Solution



Okay so I used used FOIL as if I was multiplying two binomials together so

(8√6 *√6) + (8√6 * 9√5) and (√5 *√6) + (√5 *9√5)

1) 8√6 *√6= 48 because (√n*√n= n)
2) I proceeded to use the Distribution property so 8√6 * 9√5= 72√30
3) Repeating step two with inner term: √5*√6=√30
4) Lastly inner term x outer term:√5 *√5 = √25

Okay so after using the Distribution property the new equation looks like this:
48+72√30+√30+9 √25

5) now I take take the square root of √25 which is 5 and multiply it by 9:
...9√25 becomes 45

now the equation reads:
48+72√30+√30+45

6) Now I add like terms and this is the point where I am missing a step or have messed up in some way in the above steps. After combining like terms I get:

93+73√30

the correct answer is 73√30+93

I thought addition was commutative so I didn't think that the order mattered but why when I combine 48 & 45 the sum ends up on the end of the equation and why does the order matter if addition is commutative? I got this question wrong because of the order but I've looked at this problem for a while now and I don't understand why the correct answer is in the order it is in and why it matters.

Also I'm sorry this was a long post and elementary problem but I just don't understand any clues to lead me in the right direction would be much appreciated. Thanks in advance for reading this or replying to it. And I hope this is in the right format, apologies if it isnt.

Your answer is OK: 93 + 73√30 = 73√30 + 93. Why would you think otherwise?
 
Well because it was graded as wrong and I didn't get partial credit either. I thought I followed the correct procedure but I just don't understand what exactly I did wrong.
 
Illuvitar said:
Well because it was graded as wrong and I didn't get partial credit either. I thought I followed the correct procedure but I just don't understand what exactly I did wrong.

Was this graded by a computer, or by a real person?
 
If the "correct" answer was 73√30+93 and you wrote 93 + 73√30 and this was marked wrong, go see your instructor. As already mentioned, the two expressions represent exactly the same number.
 
Ray Vickson said:
Was this graded by a computer, or by a real person?

By my instructor.

Mark44 said:
If the "correct" answer was 73√30+93 and you wrote 93 + 73√30 and this was marked wrong, go see your instructor. As already mentioned, the two expressions represent exactly the same number.

Okay. I'm sorry for the redundant thread, I just thought there was something I missed. I thought they were the same answer but was open to the idea that there was just something I didn't understand. Ill talk to my instructor. Thanks guys.
 

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