Simplify Radicals: √3 + √2 - √5

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Homework Help Overview

The discussion revolves around simplifying the expression √3 + √2 - √5. Participants are exploring the process of rationalizing the denominator and simplifying radical expressions.

Discussion Character

  • Exploratory, Mathematical reasoning, Problem interpretation

Approaches and Questions Raised

  • The original poster attempts to simplify the expression by multiplying by the conjugate and expresses confusion about the validity of canceling terms. They also question their approach to foiling the squared term.
  • Another participant points out an algebraic error in the original poster's approach and suggests that squaring the term in the denominator is necessary.
  • Some participants reflect on minor mistakes made during the process, such as sign errors.

Discussion Status

The discussion is active, with participants providing feedback on each other's attempts. Guidance has been offered regarding the algebraic steps needed to simplify the expression correctly, and there is acknowledgment of errors made in the process.

Contextual Notes

Participants are working within the constraints of homework rules, which may limit the extent of assistance they can provide to one another. There is an emphasis on understanding the steps involved in simplifying radical expressions.

AnTiFreeze3
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Homework Statement


The expression can be simplified. Simplify the following...

Homework Equations


1
_____________ - Starting equation

√3 + √2 - √5

The Attempt at a Solution



1 * [(√3 + √2) + √5]
_____________ - Multiplied by conjugate

√3 + √2 - √5 * [(√3 + √2) + √5]
√3 + √2 + √5
________________ - Next I foiled (√3 + √2)^2 and ended up with:

(√3 + √2)^2 + √5
√3 + √2 + √5
______________ - This is where I got stuck...

11 + 6√2 + √5I tried canceling out the √5 (I honestly have no clue whether you're allowed to do that at this point in the equation, please explain to me why or why not you would be able to do that) and when I did, my final solution was nowhere near the answer in the book.

I'm usually fine for problems where I need to turn a trinomial into a binomial using the associative property in order to use the conjugate to simplify, but this is the first problem that we have had where all three terms on the bottom are radicals. Did I maybe make a mistake when foiling (√3 + √2)^2... (foiling, or FOIL, is a term we use at my school, meaning First, Inner, Outer, Last, I have no idea if that's a widespread term for how to solve binomials being multiplied by each other), or am I just not seeing something else that I need to do?

Thanks in advance.

By the way, the answer that my book had in the back was:

(3√2 + 2√3 + √30)
_________________

12
 
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AnTiFreeze3 said:

Homework Statement


The expression can be simplified. Simplify the following...

Homework Equations


1
_____________ - Starting equation

√3 + √2 - √5

The Attempt at a Solution



1 * [(√3 + √2) + √5]
_____________ - Multiplied by conjugate

√3 + √2 - √5 * [(√3 + √2) + √5]

Okay, good so far.. (you might want to watch your parentheses in your last line though)

√3 + √2 + √5
________________ - Next I foiled (√3 + √2)^2 and ended up with:

(√3 + √2)^2 + √5
Okay, that step is wrong.

##
\begin{eqnarray*}
[(\sqrt{3} + \sqrt{2}) + \sqrt{5}] \cdot [(\sqrt{3} + \sqrt{2}) - \sqrt{5}] &=& (\sqrt{3} + \sqrt{2})^2 - [(\sqrt{3} + \sqrt{2}) \cdot \sqrt{5}] + [(\sqrt{3} + \sqrt{2}) \cdot \sqrt{5}] - \sqrt{5}^2 \\
&=& (\sqrt{3} + \sqrt{2})^2 - 5
\end{eqnarray*}
##

Seemed like a simple algebra error. Square the term in the denominator and the rest of the problem should be pretty easy!
 
Alright thanks, I guess I forgot to multiply the √5 by √5.
 
AnTiFreeze3 said:
Alright thanks, I guess I forgot to multiply the √5 by √5.

And a minor mistake with the + sign instead of a - sign! :smile:
 

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