Muon Decay at t=2.2x10^-6s in Frame s': Coordinates and Time

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SUMMARY

The discussion focuses on the decay of a muon at time t=2.2x10^-6 seconds in the stationary frame s, with the moving frame s' traveling at 0.9c. The decay occurs at coordinates (100, 0.8, 1.0) meters in frame s. To determine the time and coordinates of the muon decay in frame s'', the forum participant applied the time dilation formula t=(gamma)(proper time), where the proper time is 2.2x10^-6 seconds. Further calculations are necessary to find the new coordinates in frame s''.

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consider two frames s and s' where s' is moving with velocity vector (0.9c,0,0) with respect to s frame. At time t=t'=0 the origin of the two frames coincide. At time t=2.2x10^-6s a muon decays at coordinates (100,0.8,1.0) meters in the s frame.

a) At what time and coordinates does the muon decay in frame s''?


Attempt:

For this question I used the formula for time dilation to find the time the muon decays in the frame s''.

I used t=(gamma)(proper time) where the proper time is the 2.2x10^-6

How do I go about finding the new co-ordinates??
 
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