My answer for eigenspace is valid right?

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Homework Help Overview

The discussion revolves around determining the characteristic polynomials, eigenvalues, and corresponding eigenspaces of a given 2x2 matrix. Participants are examining the validity of their computed eigenspaces and comparing them to textbook answers.

Discussion Character

  • Exploratory, Assumption checking, Conceptual clarification

Approaches and Questions Raised

  • Participants present their calculations for the characteristic polynomial and eigenvalues, leading to differing representations of the eigenspace. Questions arise regarding the equivalence of these representations and the implications of scalar multiples of eigenvectors.

Discussion Status

Some participants have provided clarifications regarding the nature of eigenvectors and the dimensionality of the eigenspace. There is acknowledgment of the relationship between the different forms of the eigenspace, but no consensus on the completeness of the analysis has been reached.

Contextual Notes

One participant notes that the eigenvalue is a double eigenvalue and mentions the deficiency of the matrix's eigenspace. There is also a reference to the appropriateness of the topic within the context of calculus versus precalculus.

Rijad Hadzic
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Homework Statement


Determine the characteristic polynomials, eigenvalues, and corresponding eigenspaces of the given 2x2 matricies

Homework Equations

The Attempt at a Solution


<br /> <br /> \begin{pmatrix}<br /> 5 &amp; 2\\<br /> -8 &amp; -3 \\<br /> \end{pmatrix}<br />
thus

<br /> <br /> \begin{pmatrix}<br /> 5-\lambda &amp; 2\\<br /> -8 &amp; -3-\lambda \\<br /> \end{pmatrix}<br />

determinant is = to: \lambda^2 -2\lambda + 1

which gives value lambda = 1

plugging into <br /> <br /> \begin{pmatrix}<br /> 5-\lambda &amp; 2\\<br /> -8 &amp; -3-\lambda \\<br /> \end{pmatrix}<br />

you get<br /> <br /> \begin{pmatrix}<br /> 4 &amp; 2\\<br /> -8 &amp; -4 \\<br /> \end{pmatrix}<br />

using rref you get<br /> <br /> \begin{pmatrix}<br /> 1 &amp; .5\\<br /> 0 &amp; 0\\<br /> \end{pmatrix}<br />

setting x2 = r, I get eigenspace r*<br /> <br /> \begin{pmatrix}<br /> -1/2\\<br /> 1 \\<br /> \end{pmatrix}<br />

but my book is telling me the anser is r*<br /> <br /> \begin{pmatrix}<br /> 1\\<br /> -2 \\<br /> \end{pmatrix}<br />

our answers are the same thing right?
 
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Rijad Hadzic said:

Homework Statement


Determine the characteristic polynomials, eigenvalues, and corresponding eigenspaces of the given 2x2 matricies

Homework Equations

The Attempt at a Solution


<br /> <br /> \begin{pmatrix}<br /> 5 &amp; 2\\<br /> -8 &amp; -3 \\<br /> \end{pmatrix}<br />
thus

<br /> <br /> \begin{pmatrix}<br /> 5-\lambda &amp; 2\\<br /> -8 &amp; -3-\lambda \\<br /> \end{pmatrix}<br />

determinant is = to: \lambda^2 -2\lambda + 1

which gives value lambda = 1

plugging into<br /> <br /> \begin{pmatrix}<br /> 5-\lambda &amp; 2\\<br /> -8 &amp; -3-\lambda \\<br /> \end{pmatrix}<br />

you get<br /> <br /> \begin{pmatrix}<br /> 4 &amp; 2\\<br /> -8 &amp; -4 \\<br /> \end{pmatrix}<br />

using rref you get<br /> <br /> \begin{pmatrix}<br /> 1 &amp; .5\\<br /> 0 &amp; 0\\<br /> \end{pmatrix}<br />

setting x2 = r, I get eigenspacer*<br /> <br /> \begin{pmatrix}<br /> -1/2\\<br /> 1 \\<br /> \end{pmatrix}<br />

but my book is telling me the anser isr*<br /> <br /> \begin{pmatrix}<br /> 1\\<br /> -2 \\<br /> \end{pmatrix}<br />

our answers are the same thing right?

Of course they are. If ##v## is an eigenvector then so is ##cv## for any nonzero ##c##. Your values of ##r## just differ by a factor of -2.
 
Dick said:
Of course they are. If ##v## is an eigenvector then so is ##cv## for any nonzero ##c##. Your values of ##r## just differ by a factor of -2.

alright ty was just making sure. I do overthink small things like this but your explanation makes sense.
 
Rijad Hadzic said:

Homework Statement


Determine the characteristic polynomials, eigenvalues, and corresponding eigenspaces of the given 2x2 matricies

Homework Equations

The Attempt at a Solution


<br /> <br /> \begin{pmatrix}<br /> 5 &amp; 2\\<br /> -8 &amp; -3 \\<br /> \end{pmatrix}<br />
thus

<br /> <br /> \begin{pmatrix}<br /> 5-\lambda &amp; 2\\<br /> -8 &amp; -3-\lambda \\<br /> \end{pmatrix}<br />

determinant is = to: \lambda^2 -2\lambda + 1

which gives value lambda = 1

plugging into<br /> <br /> \begin{pmatrix}<br /> 5-\lambda &amp; 2\\<br /> -8 &amp; -3-\lambda \\<br /> \end{pmatrix}<br />

you get<br /> <br /> \begin{pmatrix}<br /> 4 &amp; 2\\<br /> -8 &amp; -4 \\<br /> \end{pmatrix}<br />

using rref you get<br /> <br /> \begin{pmatrix}<br /> 1 &amp; .5\\<br /> 0 &amp; 0\\<br /> \end{pmatrix}<br />

setting x2 = r, I get eigenspacer*<br /> <br /> \begin{pmatrix}<br /> -1/2\\<br /> 1 \\<br /> \end{pmatrix}<br />

but my book is telling me the anser isr*<br /> <br /> \begin{pmatrix}<br /> 1\\<br /> -2 \\<br /> \end{pmatrix}<br />

our answers are the same thing right?

You should point out that "1" is a double eigenvalue; that is, the eigenvalues of the matrix are 1,1. You might also want to point out that this matrix is "deficient": its "eigenspace" has only one dimension and so does not span the whole space. (It I were marking this question I would give full points only if the student mentioned those things---but of course, I am not marking it.)
 
Thread moved to Calculus section. Questions about eigen-<whatever> are well beyond precalculus, IMO.
 

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