MHB My answer:y=az^by=19.7(.454z)^0.753

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The basal metabolic rate for large anteaters is modeled by the equation y = 19.7x^0.753, where x represents the weight in kilograms. For anteaters weighing 5 kg and 25 kg, the calculated metabolic rates are approximately 66.19 kcal/day and 222.39 kcal/day, respectively. The discussion seeks assistance in converting the weight from pounds to kilograms, establishing a function x = g(z) where z is the weight in pounds. The conversion factor is noted as 1 lb = 0.454 kg, leading to a new function for weight in kilograms. Finally, the metabolic rate can be expressed as a function of weight in pounds by substituting the weight conversion into the original metabolic rate equation.
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The basal metabolic rate (in kcal/day) for large anteaters is given by:

y=f(x)= 19.7x0.753

where x is the anteater's weight in kilograms

a) find the basal metabolic rae for anteaters with the following weights

i. 5kg
ii. 25kg

My answer:

i= 66.19kg
ii= 222.39 kg

Hopefully I got a right, but b and c I need some help with please.

b) suppose the anteater's weight is given in pounds rather than kilograms. Given that 1lb=.454kg, find a function x=g(z) giving the anteater's weight in kg if z is the animals weight in lb.

c) write the basal metabolic rate as a function of the weight in pounds in the form y=azb by calculating f(g(z)).
 
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Your answers are correct thus far, the new function of kg to pounds is found by multiplying through by $\frac{1}{0.454}$
 

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