My mind has gone fallow, and I can't quite understand factoring

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The pattern is that a and p or b and p are coprime?

so how do I factorise this? a^3+ b^5+ c^7= d^11
 
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roger said:
The pattern is that a and p or b and p are coprime?

No. That is not at it at all. The counter example of a=-1, b=2 and p=3 disproves that assertion. Please, for the love of God, just think about it for one second.
 
so can anybody explain to me the factorisation of a^3+ b^5+ c^7= d^11(or impossibilty thereof)?
 
I think roger has exceeded his questions quota, and matt understandibly has lost his patience.
 
how do you find the nth term and closed form sum of : (5/12)+(12/29)+(29/70)...?
 
On the way to the definitive solution...
Obviously, numerator of the next fraction is the denominator of the previous fraction
Denominator of the next fraction equals numerator of this fraction plus sum of numerator and denominator of previous fraction