My mind has gone fallow, and I can't quite understand factoring

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    Factoring Mind
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The discussion centers on understanding how to factor numbers into coprime pairs and the implications of the number of divisors. It clarifies that the ability to express a number as a product of two coprime factors is independent of the number of divisors, with examples provided to illustrate this point. The conversation shifts to a mathematical concept from a book regarding sequences and residues, leading to confusion about the conditions under which certain pairs of residues occur. Participants emphasize the need for clarity in definitions and the application of the pigeonhole principle to understand the relationships between residues. Overall, the thread highlights the complexities of mathematical reasoning and the importance of precise communication in problem-solving.
  • #61
The pattern is that a and p or b and p are coprime?

so how do I factorise this? a^3+ b^5+ c^7= d^11
 
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  • #62
roger said:
The pattern is that a and p or b and p are coprime?

No. That is not at it at all. The counter example of a=-1, b=2 and p=3 disproves that assertion. Please, for the love of God, just think about it for one second.
 
  • #63
so can anybody explain to me the factorisation of a^3+ b^5+ c^7= d^11(or impossibilty thereof)?
 
  • #64
I think roger has exceeded his questions quota, and matt understandibly has lost his patience.
 
  • #65
how do you find the nth term and closed form sum of : (5/12)+(12/29)+(29/70)...?
 
  • #66
On the way to the definitive solution...
Obviously, numerator of the next fraction is the denominator of the previous fraction
Denominator of the next fraction equals numerator of this fraction plus sum of numerator and denominator of previous fraction
 

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