- #1

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Thank you

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- #1

- 248

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Thank you

- #2

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- #3

NascentOxygen

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It is also invaluable to be able to represent a formula as a graph to better demonstrate its dependency on a particular variable. These are skills you acquire only through practice, practice, and more practice.

- #4

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@AdityaDev could you explain dx/dt = v? Is this the same as "rate of change" change in x over change in y equals v, velocity?

- #5

SteamKing

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You can learn them but in certain situation like if acceleration is a function of time you can't use your kinematics equations.

This statement doesn't make any sense. Which kinematic equations can't you use if acceleration is a function of time? The general equations of kinematics were developed using time as the independent variable.

- #6

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dx means small change in displacement. dt means small change in time.hence dx/dt represents small change in displacement for the given small time interval.

@AdityaDev could you explain dx/dt = v? Is this the same as "rate of change" change in x over change in y equals v, velocity?

- #7

- 528

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Oh no.... You can't use the kinematic equation: V=u+at, s=ut+0.5at^2 when acceleration is varying. This is a basic assumption. Eg. a(t)=t^2+c is the acceleration at any time t. Now if you apply s=ut+... You will obviously get wrong displacement. Hence we use dv/dt = a(t)... Integrate and find v(t).This statement doesn't make any sense. Which kinematic equations can't you use if acceleration is a function of time? The general equations of kinematics were developed using time as the independent variable.

- #8

SteamKing

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