Natural Log Limits: Understanding the Use of L'Hôpital's Rule

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SUMMARY

This discussion centers on the application of L'Hôpital's Rule in solving limit problems involving natural logarithms. Participants express confusion regarding the manipulation of expressions, particularly the transformation of limits into a form suitable for L'Hôpital's Rule. The key steps involve rewriting the limit expression using natural logarithms and algebraic manipulation, specifically the use of the logarithmic identity ln(ax) = xln(a). The discussion emphasizes the importance of recognizing indeterminate forms, such as 0/0, to justify the use of L'Hôpital's Rule.

PREREQUISITES
  • Understanding of limits in calculus
  • Familiarity with L'Hôpital's Rule
  • Knowledge of natural logarithm properties
  • Basic algebraic manipulation skills
NEXT STEPS
  • Study the application of L'Hôpital's Rule in various limit scenarios
  • Explore natural logarithm properties in depth
  • Practice rewriting limit expressions to identify indeterminate forms
  • Learn advanced techniques for solving limits, including series expansion
USEFUL FOR

Students of calculus, mathematics educators, and anyone seeking to deepen their understanding of limits and L'Hôpital's Rule in mathematical analysis.

bobber205
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Can someone explain to me how they get last line to work out?
I am confused on how they're using natural log with limit problems.

Thanks for the help!

:)
 

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pics always take a while to clear, you;re better writing it up if you can
 
Didn't realize that. Sorry. :)

mathquestion1.jpg
 
bobber205 said:
Didn't realize that. Sorry. :)

mathquestion1.jpg

which equality in particular are you having a problem with? Or is it the introduction of the natural logarithm on the left-hand side?
 
I am having trouble with why he choose to let y what it does and how we went on from there.
How did he get

ln ((x+3)(x+1)/(1/x))
 
bobber205 said:
I am having trouble with why he choose to let y what it does and how we went on from there.
How did he get

ln ((x+3)(x+1)/(1/x))

This makes each term in the sequence y(x). It is also trivial that y(x) = eln(y(x)), which, in this case, is easier to study. He made use of the logarithm rule: ln(ax) = xln(a), and algebra: x = 1/(1/x), provided x is not 0.
Many limits are easily solved if you can find a clever rewriting of the algebraic expression like this.
 
How did he arrive at the 2x^2 / (x+3)(x+1) step? Is there something I'm missing he did when he took the limit to infinity?
 
bobber205 said:
How did he arrive at the 2x^2 / (x+3)(x+1) step? Is there something I'm missing he did when he took the limit to infinity?

The second limit gives us the indeterminate form 0/0, which makes it valid to use L'Hôpital's rule. This was the point of writing x as 1/(1/x).
 

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