The problem involves a tank that was initially 3/4 full of oil, then had 100 liters used, and was subsequently 2/3 full. The objective is to determine the full capacity of the tank.
There is an ongoing exploration of the mathematical relationships involved, with some participants questioning the validity of the equations proposed. Clarifications are sought regarding the interpretation of the differences between the fractions and their implications for the tank's capacity.
Participants note that the discussion is constrained by the requirement not to provide complete solutions, leading to a focus on reasoning and questioning rather than definitive answers.
tehmatriks said:Homework Statement
A tank was 3/4 full of oil. 100 litres of oil were then used. If it was then 2/3 full, how many litres does the tank hold when full
Homework Equations
The Attempt at a Solution
umm, I am not even sure how to get started, i know that 3/4 = 75% and 2/3 = 66.6%
but can't quite wrap my head around it. so yea, i need some help, thanks in advance
As stated, this isn't much help. Your equation above says that 3/4 - 2/3 = 100L, which isn't true.accystan said:Hi:
The difference between a tank that is 3/4 full and a tank that is 2/3 full is 100 litres. The word "difference" implies 'subtract'. So if (3/4 - 2/3) = 100l, what is the volume of the whole tank?
Mark44 said:As stated, this isn't much help. Your equation above says that 3/4 - 2/3 = 100L, which isn't true.
accystan said:I'm not sure why you're saying this is not true. Can you explain why?
Continuing...
If 3/4 - 2/3 = 100 l.
then 1/12 = 100 l.
and tank capacity is 1200 l.
accystan said:I'm not sure why you're saying this is not true. Can you explain why?
Continuing...
If 3/4 - 2/3 = 100 l.
then 1/12 = 100 l.
and tank capacity is 1200 l.