Need help, Activation energy determination from this reaction. Is this possible?

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SUMMARY

This discussion focuses on the determination of activation energy (Ea) for the reaction S2O82-(aq) + 2 I-(aq) --> SO42-(aq) + I2(aq) using rate constants obtained at slightly different temperatures. The user calculated Ea to be approximately 7.207 kJ/mol using the Arrhenius equation, based on rate constants of 0.0594 at 21°C and 0.06 at 22°C. The conversation highlights concerns regarding the accuracy of measurements due to a minimal temperature difference and the challenge of obtaining the frequency factor (A) necessary for direct calculations.

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himynameis
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Need help, Activation energy determination from this reaction. Is this possible??

i did an experiment, i noted the tempreture and found rate constant.
My friend did the same experiment and she found rate constant and noted the tempreture.. The tempreture differs by one degree. Can i calculate tempreture like this...?

S2O82-(aq) + 2 I-(aq) -->SO42-(aq) + I2(aq)

Friend: K1: 0.0594 at t1: 21oC = 294 K
Ours = K2: 0.06 and t2: 22oC. 295 K


In (0.0594 /0.06) = Ea / 8.314 x ( 1/ 294- 1/295 )
-0.01 = Ea / 8.31 x (1.153x10-5)
Ea= 0.01x 8.31 / 1.153x10-5)
Ea = 7207.28 J/mol

= 7.207 KJ mol

Is this possible?

please help me! :( So for this reaction is the Ea 7.207

I would have done Just used my rate constant and tempreture to wwork out Ea but I don't know the Frequency factor A! I can't find this anywhere...
 
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Your approach looks perfectly sound to me. Not that I believe in the result. 1 deg C is a very low temperature difference, especially for a typical lab thermometer. Think errors/accuracy.
 


Borek said:
Your approach looks perfectly sound to me. Not that I believe in the result. 1 deg C is a very low temperature difference, especially for a typical lab thermometer. Think errors/accuracy.

Really ? This is my friends results it was done on a different day. The only reason I had to use this method was because I did not know frequency factor. Do you know anywhere I can get frequency factors or known rate constants for particular reactions?
 


Borek said:
Your approach looks perfectly sound to me. Not that I believe in the result. 1 deg C is a very low temperature difference, especially for a typical lab thermometer. Think errors/accuracy.

thank you very much for your reply!
 


himynameis said:
Really ? This is my friends results it was done on a different day.

Doesn't matter. Experimental errors don't care about date.

The only reason I had to use this method was because I did not know frequency factor. Do you know anywhere I can get frequency factors or known rate constants for particular reactions?

They are determined with the same approach you just used. No idea where to look for the data - the best approach I know is to go to the chemistry dept library at University and ask librarian for help.
 

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