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Help I need to find out whether activation energy can be calculated this way ?

  1. Feb 2, 2012 #1
    i did an experiment, i noted the tempreture and found rate constant.
    My friend did the same experiment and she found rate constant and noted the tempreture.. The tempreture differs by one degree. Can i calculate tempreture like this...?

    S2O82-(aq) + 2 I-(aq)  SO42-(aq) + I2(aq)

    Friend: K1: 0.0594 at t1: 21oC = 294 K
    Ours = K2: 0.06 and t2: 22oC. 295 K

    In (0.0594 /0.06) = Ea / 8.314 x ( 1/ 294- 1/295 )
    -0.01 = Ea / 8.31 x (1.153x10-5)
    Ea= 0.01x 8.31 / 1.153x10-5)
    Ea = 7207.28 J/mol

    = 7.207 KJ mol

    Is this possible?

    please help me!! :( So for this reaction is the Ea 7.207

    I would have done Just used my rate constant and tempreture to wwork out Ea but I dont know the Frequency factor A! I cant find this anywhere...
  2. jcsd
  3. Feb 2, 2012 #2
    can anyone help me is this possible?
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