1. Limited time only! Sign up for a free 30min personal tutor trial with Chegg Tutors
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Need Help- Finding the tension and Force wind using newton's laws

  1. Oct 26, 2012 #1
    1. The problem statement, all variables and given/known data
    A 1.20 g spider hangs on its thread from the branch of a tree. A horizontal win blows the spider and the tread to an angle of 35 deg from the vertical. Find the force of win on the sider and the tension in the tread.

    Diagram:
    http://s1176.beta.photobucket.com/user/LolaGoesLala/media/g.jpg.html


    2. Relevant equations
    Fnet= Fg + Fw + Tcosθ + Tsinθ


    3. The attempt at a solution

    Fg = mg
    Fg= (0.0012 kg)(9.8 m/s^2)
    Fg= 0.01176 N

    Fnet = 0.01176 N + Fw + Tcos55° + Tsin55°
    I got the 55° by subtracting the 35° from 90°

    Vertical equilibrium:
    0.01176 N = Tsin55°
    0.014356 N = T

    Horizontal equilibrium:
    Tcos55°=Fw
    (0.014356 N)(cos55°)=Fw
    0.00823 N = Fw
     
  2. jcsd
  3. Oct 26, 2012 #2

    tiny-tim

    User Avatar
    Science Advisor
    Homework Helper

    Hi Lolagoeslala! :smile:

    Yes, that looks ok.

    Two points …

    i] why did you convert from 35° to 55°? it's correct, but it's unnecessary, and it gives you an extra chance to make a mistake!

    ii] your line "Fnet= Fg + Fw + Tcosθ + Tsinθ" is simply wrong
    (but it didn't matter, because your component equations were correct, so you didn't need that line)
    … you can't add components in different directions!

    correct would be "Fnet = Fg + Fw + T"

    or "Fnet = Fg + Fw + (Tcosθ,Tsinθ)" :wink:
     
  4. Oct 26, 2012 #3
    Oh akay by the way for your first point how you are like why did you convert to 55° from 35°
    is because when i was making the FBD.... i needed the angle of the horizontal. But how would you take the 35° and work with that.... i have not learned how to work with angles that are like on the opposite sides.
     
  5. Oct 26, 2012 #4

    tiny-tim

    User Avatar
    Science Advisor
    Homework Helper

    ah, this is elementary Euclidean geometry …

    if you have a letter "N", the two angles are equal (i think they're called "alternate angles") …

    so the "downward" angle (35°) between the thread and the vertical wall is the same as the "upward" angle between the thread and the imaginary vertical through the spider :wink:

    (the thread corresponds to the diagonal of the "N")
     
  6. Oct 26, 2012 #5
    Oh i know that LOLLL :D
    Thanks for reviewing my memory :D thanks for checking by the way :D
     
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook




Similar Discussions: Need Help- Finding the tension and Force wind using newton's laws
Loading...