Newton's Laws/ Tension Forces Problem

BEANTOWN
Messages
5
Reaction score
0

Homework Statement



Two Objects are hung from strings. The top object (m1) has a mass of 18 kg and the bottopm object (m2) has a mass of 12 kg.

Looks like this:
http://www.google.ca/imgres?q=physi...w=158&start=0&ndsp=15&ved=1t:429,r:6,s:0,i:77

(a). Calculate tension in each string.

(b) Calculate the tension in each string if you pull down on m1 with a force of 45 N [down]

Homework Equations



FNet = ma
Fg = mg
g = 9.8

The Attempt at a Solution


I knew how to do (a).
I creted a free body diagram for each weight first.
Then for m1:
FNet = T1 - Fg
0 = T1 - Fg ----> FNet = 0 because it is at rest
T1 = Fg
T1 = (18)(9.8)
T1= 176.4 N
And then i did the same for the second one, and came up with T2 = 117.6

Then I got to (b). But I am lost.
I attemted to find acceleration by doing:
FNet = Fa ----> Fa = the 45 N
FNet = 45 N
ma = 45 N
(m1 + m2)a= 45 ---- a= 45/(18 + 12)
a = 1.5
So:
FNet = T1 - Fg1
(18)(1.5) + (9.8)(18) = T1
T1 = 203.4 N
According to my answer key, this is not right. Please help.
 
on Phys.org
BEANTOWN said:

Homework Statement



Two Objects are hung from strings. The top object (m1) has a mass of 18 kg and the bottopm object (m2) has a mass of 12 kg.

Looks like this:
http://www.google.ca/imgres?q=physi...w=158&start=0&ndsp=15&ved=1t:429,r:6,s:0,i:77

(a). Calculate tension in each string.

(b) Calculate the tension in each string if you pull down on m1 with a force of 45 N [down]

Homework Equations



FNet = ma
Fg = mg
g = 9.8

The Attempt at a Solution


I knew how to do (a).
I creted a free body diagram for each weight first.
Then for m1:
FNet = T1 - Fg
0 = T1 - Fg ----> FNet = 0 because it is at rest
T1 = Fg
T1 = (18)(9.8)
T1= 176.4 N
And then i did the same for the second one, and came up with T2 = 117.6

Then I got to (b). But I am lost.
I attemted to find acceleration by doing:
FNet = Fa ----> Fa = the 45 N
FNet = 45 N
ma = 45 N
(m1 + m2)a= 45 ---- a= 45/(18 + 12)
a = 1.5
So:
FNet = T1 - Fg1
(18)(1.5) + (9.8)(18) = T1
T1 = 203.4 N
According to my answer key, this is not right. Please help.

Red line above.

T1 is supporting BOTH masses so the mass used to calculate T1 should be 30kg.

T2 is supporting only M2 so your answer is probably correct.

With a free body diagram:-

for M2:

M2g down, T2 up so your answer should be correct

for M1:

M1g down + T2 down, T1 up

For part b, there is no acceleration; merely an EXTRA 45N down in the free body diagram for M1
 

Similar threads

  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 24 ·
Replies
24
Views
10K
  • · Replies 3 ·
Replies
3
Views
2K
Replies
4
Views
4K
Replies
3
Views
3K
  • · Replies 17 ·
Replies
17
Views
4K
Replies
1
Views
3K
  • · Replies 5 ·
Replies
5
Views
3K
  • · Replies 45 ·
2
Replies
45
Views
24K
  • · Replies 15 ·
Replies
15
Views
11K