Need help on how they got these numbers -- solution to a trig equation

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The discussion centers on solving the trigonometric equation 4sin²(θ) - 5.4326sin(θ) + 1.4602 = 0. Participants clarify that the equation can be transformed into a standard quadratic form by letting x = sin(θ), resulting in 4x² - 5.4326x + 1.4602 = 0. The solution involves either completing the square or applying the quadratic formula. It is noted that this equation has complex roots, indicating that it does not yield real values for θ.

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Summary:: This is not a homework i just need clarification on how they got those number
Any solution involving sine and cosine is my weakness when its advance or intermediate

IMG_20200223_191358.jpg
 
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Do you know how to solve ##ax^2+bx+c=0##?

... and it does belong into our homework forums, whether it is or not.
 
Let x= sin(\theta). Then 9sin^2(\theta)- 5.4326sin(\theta)+ 1.4602= 0 becomes 9x^2- 5.4326x+ 1.4602= 0. Solve for x by "completing the square" or using the quadratic formula.

However, this equation has only complex roots so will not give the values of \theta you have. Are you sure you have copied it correctly?
 
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Thank you
 
AzureSekki said:
Summary:: This is not a homework i just need clarification on how they got those number
Any solution involving sine and cosine is my weakness when its advance or intermediate

View attachment 257521
It's generally recommended that type the problem statement.

It seems that the problem you wrote and then photographed is:
## 4\sin^2(\theta)- 5.4326\sin(\theta)+ 1.4602= 0 ##

It's difficult to see that the first coefficient is a 4 and not a 9 .
 

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