Hey guys, I just wanted to come here and see if anyone could help me out. I am getting stuck using the trig formulas for summing sines and cosines. I won't beat around the bush too much, so let's get right into it. 1. The problem statement, all variables and given/known data Use a trig formula to write the two terms as a single harmonic. sin(2x) + sin(2(x+(pi/3))) 2. Relevant equations sin(A+B) = sinA*cosB + sinB*cosA cos(A+B) = cosA*cosB - sinA*sinB sin^2(A) + cos^2(A) = 1 3. The attempt at a solution So I think that I might be over-thinking this, or maybe I am just not recognizing some pattern which would lead me to the solution. I'll walk through my steps: 1. I assume that to solve this, I should expand these two functions with the trig formulas I mentioned above. I am hoping that in doing so, I can combine like terms and find a single sine or cosine function which gives me all the information I need. 2. The given problem is equivalent to the expression: sin2x + sin(2x + 2pi/3) 3. From that follows: 2*sinx*cosx + sin2x*cos(2*pi/3) + cos2x*sin(2*pi/3) 4. From that, I get: 2*sinx*cosx - (1/2)sin2x - (sqrt(3)/2)cos2x 5. Following that: 2*sinx*cosx - sinx*cosx - (sqrt(3)/2)(cos^2(x) - sin^2(x)) 6. Then I get: sinx*cosx - (sqrt(3)/2)(cos^2(x) - sin^2(x)) 7. Which ultimately leads me to: (1/2)sin2x - (sqrt(3)/2)cos2x Step seven is where I get stuck. I honestly have no clue where to go from here. Any tips or hints would be greatly appreciated!!