What weight does the scale read when a man squats with an acceleration downward?

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SUMMARY

The discussion centers on the physics of a man squatting on a balance scale reading 80kg while accelerating downward. The correct interpretation is that the normal force (N) increases when the man squats, leading to a scale reading greater than 80kg, confirming option (B). The confusion arises from misinterpretation of the forces involved, specifically the equations N=mg and N=m(g+a). A scenario of free-falling while squatting would result in the scale reading zero, as the normal force would not be acting.

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bem
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my pre-test has a question: "A man is standing on a balance scale which reads 80kg. Suddenly, he quats with a n acceleration a (downward). What weight does the scale read while the man is squatting?
(A)the same (B) more than 80kg (c) less than 80kg

I chosed (b)
because before we have N=mg
then after the man squatting N=m(g+a)
so the scale has to read more than 80kg. But then one of my friend said that N=m(g-a). I'm just confused. Can smbd help me ? I have a bet with him ( 10 bucks, hehe).
 
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Bem,

Consider the ultimate squat. What if the man squatted REALLY fast - i.e. he lifts his legs up off the scale and free falls. What would the scale read in that case?
 


Your reasoning is correct. When the man squats with an acceleration downward, the normal force acting on him will increase. This means that the scale will read a higher weight, which is option (b). Your friend may have made a mistake in their calculation or interpretation of the question. If you are unsure, you can always double check with a teacher or tutor to confirm your answer. Good luck with your bet!
 

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