[/B]1. The problem statement, all variables and given/known data[/b](adsbygoogle = window.adsbygoogle || []).push({});

A cat walks along a uniform plank that is 4.00 m long and has a mass of 7.00 kg. The plank is supported by two sawhorses, one 0.44 m from the left end of the board and the other 1.58 m from its right end. When the cat nears the right end, the plank just begins to tip. If the cat has a mass of 5.4 kg, how close to the right end of the two-by-four can it walk before the board begins to tip?

2. Relevant equations

F1 + F2 -mg = 0;

3. The attempt at a solution

This problem is probably really easy but I have been looking at problems similar to it in my textbook and online and I think that's making me more confused. I have tried a lot of different things to solve this

For the left side of the 2nd sawhorse I need to find the length of the left side of the board. Is the length just 4-1.50 = 2.5 or is it the distance between the two sawhorses?. 4-(1.50+.44)= 1.98?

If it is the second case:

1.98m/4 = .495(7kg*9.81m/s2) = 33.99N

so if someone can tell me if I am on the right track I would really appreciate

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# Homework Help: NEED HELP! Rotational dynamics and static equilibrium

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