[/B]1. The problem statement, all variables and given/known data[/b](adsbygoogle = window.adsbygoogle || []).push({});

A cat walks along a uniform plank that is 4.00 m long and has a mass of 7.00 kg. The plank is supported by two sawhorses, one 0.44 m from the left end of the board and the other 1.58 m from its right end. When the cat nears the right end, the plank just begins to tip. If the cat has a mass of 5.4 kg, how close to the right end of the two-by-four can it walk before the board begins to tip?

2. Relevant equations

F1 + F2 -mg = 0;

3. The attempt at a solution

This problem is probably really easy but I have been looking at problems similar to it in my textbook and online and I think that's making me more confused. I have tried a lot of different things to solve this

For the left side of the 2nd sawhorse I need to find the length of the left side of the board. Is the length just 4-1.50 = 2.5 or is it the distance between the two sawhorses?. 4-(1.50+.44)= 1.98?

If it is the second case:

1.98m/4 = .495(7kg*9.81m/s2) = 33.99N

so if someone can tell me if I am on the right track I would really appreciate

**Physics Forums | Science Articles, Homework Help, Discussion**

Join Physics Forums Today!

The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

# NEED HELP! Rotational dynamics and static equilibrium

**Physics Forums | Science Articles, Homework Help, Discussion**