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Need help tonight- Integration Buoyancy Problem

  • Thread starter bcjochim07
  • Start date
  • #1
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1. Homework Statement
A 4 cm diameter cylinder floats in the water. How much work must be done to push the cylinder 10 cm deeper into the water?


2. Homework Equations



3. The Attempt at a Solution

I did the integral from 0 to .1 m of (.02m)^2 * pi * (1000kg/m^3) * (9.80) * x dx

= (12.3 x^2)/2 evaluated from 0 to .1 = .0615 J. However, the back of my book says .615 J. Somehow I ended up a decimal place off. Could someone help me?
 

Answers and Replies

  • #2
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Ok, so I found out the book had a typo in it, and my answer was correct.
 
  • #3
Doc Al
Mentor
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I'd say that you are right and the book is wrong.

(Oops... too late! You must have posted while I was distracted in mid post.)
 
Last edited:

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