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Need help tonight- Integration Buoyancy Problem

  1. Apr 30, 2008 #1
    1. The problem statement, all variables and given/known data
    A 4 cm diameter cylinder floats in the water. How much work must be done to push the cylinder 10 cm deeper into the water?

    2. Relevant equations

    3. The attempt at a solution

    I did the integral from 0 to .1 m of (.02m)^2 * pi * (1000kg/m^3) * (9.80) * x dx

    = (12.3 x^2)/2 evaluated from 0 to .1 = .0615 J. However, the back of my book says .615 J. Somehow I ended up a decimal place off. Could someone help me?
  2. jcsd
  3. Apr 30, 2008 #2
    Ok, so I found out the book had a typo in it, and my answer was correct.
  4. Apr 30, 2008 #3

    Doc Al

    User Avatar

    Staff: Mentor

    I'd say that you are right and the book is wrong.

    (Oops... too late! You must have posted while I was distracted in mid post.)
    Last edited: Apr 30, 2008
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