Need Help Understanding Heat of Rxn and Q

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SUMMARY

The discussion focuses on the distinction between the heat of reaction (Hrxn) and the heat transfer (q) in a chemical reaction involving calcium (Ca). The participant calculated q using the formula q = mCat, resulting in 24766.5 J for the heat released from 1.25 grams of Ca. They initially miscalculated the total heat by incorrectly dividing q by the number of moles (0.03), leading to confusion. The correct approach emphasizes maintaining precision in calculations to avoid rounding errors, ultimately yielding a corrected value of 794052 J.

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Lori

Homework Statement



upload_2017-12-13_21-25-11.png

Homework Equations



q = mCat

The Attempt at a Solution


I'm kinda confused the different between Hrxn and q? I know the reaction warms the water with q=mcat = 150*4.18*(59.5-20)=24766.5 J. This is the heat released from 1.25 grams of Ca which is 0.03 moles of Ca. But, the reaction equation only have calcium per 1 mole so i thought that i would divide q by 0.03 = 825550 J or 825KJ, but this is not an answer.

Can someone help me with these heat problems? Thanks
 

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Nevermind everyone. It seems like i didn't enter enough decimals here. So, my answer is 794052
 
Exactly. Don't round down intermediate results during calculations (that is, report them rounded down, but calculate with a full accuracy, or at least several "guard digits").
 
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