Need help using Ion Electron Method in acidic conditions.

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SUMMARY

The discussion focuses on the application of the Ion Electron Method for balancing the redox reaction between permanganate ions (MnO4-) and oxalate ions (C2O42-) in acidic conditions. The user attempted to balance the half-reactions separately, resulting in the equations MnO4- + 8H+ -> Mn2+ + 4H2O and C2O42- + 4H+ -> CO2 + 2H2O. However, the user encountered difficulties in balancing the electrons, leading to an incorrect final equation. The key takeaway is that balancing carbon first is essential, and water should be introduced in subsequent steps for accurate results.

PREREQUISITES
  • Understanding of redox reactions and half-reaction method
  • Familiarity with balancing chemical equations in acidic conditions
  • Knowledge of oxidation states and electron transfer
  • Basic skills in manipulating chemical formulas and coefficients
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  • Study the Ion Electron Method for balancing redox reactions in detail
  • Learn about oxidation states and how to determine them in complex reactions
  • Practice balancing various redox reactions in acidic and basic conditions
  • Explore common pitfalls in balancing chemical equations and how to avoid them
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Chemistry students, educators, and professionals involved in chemical analysis or redox reaction studies will benefit from this discussion, particularly those focusing on balancing equations in acidic environments.

thyrgle
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Using the Ion Electron Method (acidic conditions) I need to solve:

MnO4- + C2O42- -> Mn2+ + CO2

So I tried doing:

MnO4- -> Mn2+

And:

C2O42- -> CO2 + 2H2O

Then I balanced the oxygen atoms with H2O

MnO4- -> Mn2+ + 4H2O

And:

C2O42- -> CO2 + 2H2O

Then I added the hydrogen atoms:

MnO4- + 8H+ -> Mn2+ + 4H2O

And:

C2O42- + 4H+ -> CO2 + 2H2O

Then I tried balancing the electrons and I got -3e for the first equation and -2e for the second. Then I tried combining the two:

2MnO4- + 16H+ +
3C2O42- + 12H+ -> 2Mn2+ + 8H2O + 3CO2 + 6H2O

Cancel out the H+ and H2O:

2MnO4- + 28H+ +
3C2O42- -> 2Mn2+ + 14H2O + 3CO2

I don't know if there is something else I should do (which I suspect there is but I can't tell), and I think I am doing something wrong because my answer didn't turn out right. Any help would be appreciated.
 
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thyrgle said:
C2O42- -> CO2 + 2H2O

You should balance carbon first. H2O - if needed - should appear in the next step.
 

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