Need help with stable-unstable cores(cells)

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Discussion Overview

The discussion revolves around the concepts of binary energy and binding energy in relation to the stability of atomic nuclei. Participants explore the relationship between energy levels and nuclear stability, questioning why certain nuclei with higher binding energy are not necessarily more stable than those with lower binding energy.

Discussion Character

  • Exploratory, Technical explanation, Debate/contested

Main Points Raised

  • One participant questions why an atom with higher binary energy (Eb) is not more stable than one with lower Eb, despite having the same nucleon number (A).
  • Another participant clarifies that "binary energy" likely refers to "binding energy" and explains that an atom can decay into another atom of the same nucleon number if the latter has a larger binding energy.
  • A follow-up inquiry seeks to understand which of the two atoms (K or L) is more stable and the reasoning behind it.
  • One participant notes that if both atoms are unstable, their lifetimes cannot be generalized and depend on various factors such as nuclear spin and the parity of proton/neutron numbers.
  • It is asserted that the scenario of an unstable atom with larger binding energy decaying into a stable atom with smaller binding energy is not possible, assuming electron capture is neglected.

Areas of Agreement / Disagreement

Participants express differing views on the relationship between binding energy and stability, with some asserting that higher binding energy does not guarantee stability, while others provide conditions under which decay occurs. The discussion remains unresolved regarding the implications of binding energy on stability.

Contextual Notes

Participants mention various factors influencing nuclear stability, including nuclear spin and the parity of nucleon numbers, which may not have been fully explored in the discussion.

radioactive8
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Hi...!
I was trying to understand the meaning of the binary Energy (Eb) ..
For example :
Imagine we have two cores ... 1 from an X atom and 1 from an Y atom which have the same A and X has bigger Eb than Y ... while Y is the stable core for that exact A ...
That means
Because energy is never lost
Eb + EY = Ep + En ⇔ ... ⇔

Eb = ( ZMp + NMn - MY )c2

But what i can't understand is the following

Why isn't X more stable as it has bigger binary energy therefore the same number of protons and netrons are hold by bigger power ?

HOWEVER if we look at the opposite way
Why isn't any core with smaller binary energy and same A than X stablier because its stableness would require less energy ...

But our researches have shown that both above are not true ... but why ?
 
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What is "binary energy"? Do you mean "binding energy"?

An atom K can decay into another atom L of the same nucleon number if L has a larger binding energy, the opposite is not possible neglecting electron capture[/size].
 
What is "binary energy"? Do you mean "binding energy"?

Yes

An atom K can decay into another atom L of the same nucleon number if L has a larger binding energy, the opposite is not possible neglecting electron capture.

This doent answer my question ...
I am wondering about which cell is stablier K or L (fro your example ) .. and why ...
 
If both are unstable, there is no general rule for their lifetimes, it depends on too many other factors (like nuclear spin, odd/even proton/neutron numbers and so on). The setup you described in post 1 (instable atom with larger binding energy decaying to stable atom with smaller binding energy) is not possible. Again, neglecting electron capture.[/size]
 

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