Need help with stable-unstable cores(cells)

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SUMMARY

The discussion centers on the concepts of binary energy (Eb) and binding energy in nuclear physics, specifically comparing the stability of atomic cores. It establishes that an atom with a larger binding energy, such as atom L, can decay from a less stable atom K, but not vice versa. The conversation clarifies that stability is influenced by multiple factors beyond just binding energy, including nuclear spin and the parity of proton and neutron numbers. The participants conclude that the relationship between binding energy and stability is complex and cannot be simplified to a direct correlation.

PREREQUISITES
  • Understanding of nuclear physics concepts, specifically binding energy.
  • Familiarity with atomic structure, including protons and neutrons.
  • Knowledge of nuclear decay processes and stability criteria.
  • Basic grasp of energy conservation principles in nuclear reactions.
NEXT STEPS
  • Research the concept of binding energy in detail, focusing on its role in nuclear stability.
  • Explore the factors affecting nuclear decay rates, including nuclear spin and parity of nucleons.
  • Study examples of stable and unstable isotopes to understand their binding energy characteristics.
  • Learn about electron capture and its implications in nuclear decay processes.
USEFUL FOR

Students and professionals in nuclear physics, researchers studying atomic stability, and educators looking to deepen their understanding of binding energy and nuclear decay mechanisms.

radioactive8
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Hi...!
I was trying to understand the meaning of the binary Energy (Eb) ..
For example :
Imagine we have two cores ... 1 from an X atom and 1 from an Y atom which have the same A and X has bigger Eb than Y ... while Y is the stable core for that exact A ...
That means
Because energy is never lost
Eb + EY = Ep + En ⇔ ... ⇔

Eb = ( ZMp + NMn - MY )c2

But what i can't understand is the following

Why isn't X more stable as it has bigger binary energy therefore the same number of protons and netrons are hold by bigger power ?

HOWEVER if we look at the opposite way
Why isn't any core with smaller binary energy and same A than X stablier because its stableness would require less energy ...

But our researches have shown that both above are not true ... but why ?
 
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What is "binary energy"? Do you mean "binding energy"?

An atom K can decay into another atom L of the same nucleon number if L has a larger binding energy, the opposite is not possible neglecting electron capture[/size].
 
What is "binary energy"? Do you mean "binding energy"?

Yes

An atom K can decay into another atom L of the same nucleon number if L has a larger binding energy, the opposite is not possible neglecting electron capture.

This doent answer my question ...
I am wondering about which cell is stablier K or L (fro your example ) .. and why ...
 
If both are unstable, there is no general rule for their lifetimes, it depends on too many other factors (like nuclear spin, odd/even proton/neutron numbers and so on). The setup you described in post 1 (instable atom with larger binding energy decaying to stable atom with smaller binding energy) is not possible. Again, neglecting electron capture.[/size]
 

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