Noah332
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- TL;DR
- Trying to build a structure but not sure if i am doing it correctly
So given a force F that is at r1/2, distances y, r1,r2,and r3. What is x?
The discussion revolves around a statics problem related to designing a structure capable of supporting a 1300 lb supersack filled with walnuts. Participants explore various aspects of the structural design, including forces, distances, and materials, while addressing safety concerns.
Participants express varying opinions on the necessary constraints for the beam length and the overall design approach. There is no consensus on the best method to ensure stability and safety, highlighting multiple competing views.
Participants note the importance of considering the center of gravity and the potential for tipping, but there are unresolved questions regarding the specific calculations and design parameters needed for safety.
This discussion may be useful for individuals interested in structural engineering, statics, or those involved in practical applications of load-bearing designs.
Since you have given us no idea what constrains you want to put on x, how could we know? What is it you are trying to achieve?Noah332 said:What is x?
? x is a DISTANCE, not a force, at least the way you have it drawn.Noah332 said:Does x need to have a constraint? Its a statics problem. I figured u sum up the forces in the x direction, sum up the forces in the y direction and sum of the moments and solve for x. Seems pretty straight forward I am just trying to check if i did it right so i want to see how someone who knows what they are doing, does it? The one thing i realized i left out is the angle of those angled beams. They should be 45 degrees.
Noah332 said:Yes exactly. Its a distance. I need to figure out how long that beam should be so thing thing doesn't fall over from the weight.
Well, that's trivial. x has be be a minimum of r1/2 + r2 - r3. In practice you'll want it a bit longer. Personally, I'd go with x = r1 + r2 - r3Noah332 said:Yes exactly. Its a distance. I need to figure out how long that beam should be so thing thing doesn't fall over from the weight.
If it was my job, I would want the front support at least 2 feet past the center of gravity of the 1300 lb load. Preferably a little more, or a lot more depending on the height. And anchor it to the floor.phinds said:Well, that's trivial. x has be be a minimum of r1/2 + r2 - r3. In practice you'll want it a bit longer. Personally, I'd go with x = r1 + r2 - r3
Sure, but he gave a very simplistic problem and I gave him a simplistic answer.jrmichler said:You want to hold a 1300 load, but don't know how to keep it from tipping over. I strongly suggest talking to a real engineer.
BTW, those angle braces do exactly nothing for the strength of the vertical column. Can you explain why?If it was my job, I would want the front support at least 2 feet past the center of gravity of the 1300 lb load. Preferably a little more, or a lot more depending on the height. And anchor it to the floor.
As far as that goes, what keeps it from tipping over sideways?jrmichler said:You want to hold a 1300 load, but don't know how to keep it from tipping over.
Its being built out of steeldavenn said:and what are you wanting to build the structure from ?
anything less than very strong and it will buckle long before it topples over
Well it will have two of those side frames about 4 ft apart with connected cross beamssandy stone said:As far as that goes, what keeps it from tipping over sideways?
One at each cornerNoah332 said:Well it will have two of those side frames about 4 ft apart with connected cross beams
I wanted to see how you would use statics. Like sum the forces and the moments. I wanted to see how its donephinds said:Sure, but he gave a very simplistic problem and I gave him a simplistic answer.