Need help with this(dimensional analysis)

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The discussion centers on the relationship between the velocity 'v' of a liquid through a nozzle and its pressure drop 'P' and density 'p'. The established equation is v = C(P/p)^(1/2), where 'C' is a constant. Participants emphasize the importance of expressing 'v', 'P', and 'ρ' in terms of fundamental units: kilograms (kg), meters (m), and seconds (s) to clarify the dimensional analysis. This approach simplifies understanding the relationship between these variables.

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It is observed that the velocity 'v' of a liquid having a nozzle depends upon the pressure drop 'P'and the density'p'.Show that the relationship between them is of the form.


v=C[P/p]raised to power of 1/2
 
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allaputa said:
It is observed that the velocity 'v' of a liquid having a nozzle depends upon the pressure drop 'P'and the density'p'.Show that the relationship between them is of the form.


v=C[P/p]raised to power of 1/2


What are your thoughts? What do you know?

Write v, P and [itex]\rho[/itex] in terms of the three fundamental units: kg, meter and second. Then the answer should be obvious.

Patrick
 
I don't think anyone is going to miss the equation...:wink:
 

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