The discussion centers on calculating the work done when a 1150 kg car accelerates from 2 m/s to 6 m/s. The correct formula to use is the change in kinetic energy (KE), expressed as Work done = 0.5 * mass * (final velocity² - initial velocity²). By applying this formula, the work done is calculated as Work done = 0.5 * 1150 * (6² - 2²), resulting in a definitive value of work done.
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kylepetten said:Homework Statement
Calculate how much work is done when a 1150 kg car accelerates from 2 m/s to 6m/s
Homework Equations
The Attempt at a Solution
I have no idea. It seems like insufficient information to me. Please help! I am in great need as my exam is drawing near!
Thanks!
inky said:Work done=change in KE=0.5*1150(6^2-3^2)