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Need to find two currents in this circuit

  1. Feb 2, 2008 #1
    I am trying to find the currents I_D1 and I_D2 labeled in the picture by the arrows. I am stumped on how to obtain the correct values for the currents. I am having trouble using either KCL or KVL. This circuit seems simple but has me stumped.

    [​IMG]

    If I write KCL at the node to the right of the I_D1 arrow I get

    [tex]-I_{D1}+I_{D2}-I_{6V}=0 \implies [/tex]

    [tex] I_{D1}=I_{D2}-I_{6V}.[/tex]

    [tex]I_{6V}=\frac{6V}{43k\Omega}=140\mu A[/tex]

    [tex]I_{D2}=\frac{9V}{22k\Omega}=409\mu A[/tex]

    Is there an easier or different way to do this problem, perhaps using KVL instead of writing a KCL equation at the node I used?

    Thanks
     
    Last edited: Feb 2, 2008
  2. jcsd
  3. Feb 2, 2008 #2

    Defennder

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    Homework Helper

    Yes you can also do it via mesh analysis. You would have 2 equations here.
     
  4. Feb 3, 2008 #3

    CEL

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    The simplest way to solve the circuit is the one you used.
     
  5. Feb 5, 2008 #4
    Quick solution:

    Hey this is a simple mesh anaylisis problem.. I've included a solution. I hope it helps. Cheers
     

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