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opticaltempest

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I am trying to find the currents I_D1 and I_D2 labeled in the picture by the arrows. I am stumped on how to obtain the correct values for the currents. I am having trouble using either KCL or KVL. This circuit seems simple but has me stumped.

http://img127.imageshack.us/img127/8600/circuitvz9.jpg

If I write KCL at the node to the right of the I_D1 arrow I get

[tex]-I_{D1}+I_{D2}-I_{6V}=0 \implies [/tex]

[tex] I_{D1}=I_{D2}-I_{6V}.[/tex]

[tex]I_{6V}=\frac{6V}{43k\Omega}=140\mu A[/tex]

[tex]I_{D2}=\frac{9V}{22k\Omega}=409\mu A[/tex]

Is there an easier or different way to do this problem, perhaps using KVL instead of writing a KCL equation at the node I used?

Thanks

http://img127.imageshack.us/img127/8600/circuitvz9.jpg

If I write KCL at the node to the right of the I_D1 arrow I get

[tex]-I_{D1}+I_{D2}-I_{6V}=0 \implies [/tex]

[tex] I_{D1}=I_{D2}-I_{6V}.[/tex]

[tex]I_{6V}=\frac{6V}{43k\Omega}=140\mu A[/tex]

[tex]I_{D2}=\frac{9V}{22k\Omega}=409\mu A[/tex]

Is there an easier or different way to do this problem, perhaps using KVL instead of writing a KCL equation at the node I used?

Thanks

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