Need to know how to solve for test

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SUMMARY

The discussion focuses on solving a physics problem involving a 2.0 kg box on a 65-degree inclined plank, attached to a spring with a force constant of 295 N/m. The maximum stretch of the spring while keeping the box at rest is determined to be 6.6 cm. To find this stretch, one must resolve the gravitational force into components along and perpendicular to the plank, calculate the static friction using a coefficient of 0.19, and set the sum of forces to zero to find the necessary force for equilibrium.

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  • Knowledge of static friction and its coefficient
  • Ability to resolve forces into components
  • Familiarity with Hooke's Law and spring constants
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A 2.0kg box rests on a plank that is inclined at a angle of 65 degrees above the horizontal. The upper end of the box is attached to a spring with a force constant of 295 N/m. If the coefficient of the static friction between the box and the plank is 0.19, what is the maximum amount the spring can be stretched and the box remain at rest?

Can someone show me how to complete this problem. The answer is 6.6cm however I don't know to get there. thanks

I also know that I have to find force and divide that by 295N/M to get answer can someone help me find force please! What numbers do I use
 
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Get expressions for the forces on the box in the direction of the plank. You'll need to resolve the mg force into a component along the plank and another perpendicular to the plank that you can use to find the friction forces. Set the sum of the forces equal to zero - the point where it will just begin to move. That should allow you to solve for the stretch.
 

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