Need to make sure I am doing these problems correctly.

  • Thread starter Thread starter Jdpaul88
  • Start date Start date
Click For Summary

Homework Help Overview

The discussion revolves around measurement problems related to mass, weight, and unit conversion, specifically focusing on the weights of pints of English Bitter and pure clear water.

Discussion Character

  • Exploratory, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • The original poster attempts to calculate the weight of a pint of English Bitter and pure clear water using given mass and conversion factors. They question the correctness of their method for part a and seek confirmation before proceeding to parts b and c.

Discussion Status

Some participants have acknowledged the original poster's method as acceptable but have not provided detailed verification of the calculations. The conversation remains open, with the original poster seeking further validation of their approach.

Contextual Notes

The original poster is working under the constraints of a homework assignment, which may impose specific requirements for the calculations and conversions involved.

Jdpaul88
Messages
8
Reaction score
0
Measurement problems: Mass, weight, unit conversion

Homework Statement


There are 8 pints to a gallon. One gallon of good English Bitter, ready to drink, has a mass of 3.831 Kg. One gallon of pure clear water, also at drinking temperature, has a mass of 3.785 Kg. A pound, on the other hand, is anything that has a mass of 0.4535 Kg. There are, by definition, 16 ounces in a pound

a. How heavy is a pint of English Bitter in pounds
b. How heavy is a pint of pure clear water in pounds
c. How much more massive is a pint of Bitter than a pint of water in ounces?


Homework Equations


1 galbitter = 3.831 Kg
1 galpure = 3.785
1 gal = 8 pints
1 lb = 0.4535 Kg
1 lb = 16 ounces



The Attempt at a Solution



So, for a I took 1 galbitter= (3.831Kg/1gal) x (1lb/0.4535Kg) = 8.44762955 lbs per gallon of bitter. I then took 8.447562955 lbs per gallon of bitter/8pints
8.447562955/8 to get the weight of 1 pint of bitter? Is this the correct way to do point a? If it is then I can do point b, no problem. And for point c, I can just subtract and find the difference after multiplying the weights of each pint of liquid by 16 oz, right?
 
Last edited:
Physics news on Phys.org


Jdpaul88 said:

Homework Statement



Homework Equations


1 galbitter = 3.831 Kg
1 galpure = 3.785
1 gal = 8 pints
1 lb = 0.4535 Kg
1 lb = 16 ounces

The Attempt at a Solution



So, for a I took 1 galbitter= (3.831Kg/1gal) x (1lb/0.4535Kg) = 8.44762955 lbs per gallon of bitter. I then took 8.447562955 lbs per gallon of bitter/8pints
8.447562955/8 to get the weight of 1 pint of bitter? Is this the correct way to do point a? If it is then I can do point b, no problem. And for point c, I can just subtract and find the difference after multiplying the weights of each pint of liquid by 16 oz, right?

Your method looks ok. I didn't run your numbers. Good luck and Welcome to PF.
 


LowlyPion said:
Your method looks ok. I didn't run your numbers. Good luck and Welcome to PF.

Thanks for the input. Good to meet you.
 


Jdpaul88 said:
Thanks for the input. Good to meet you.

Cheers then.

Enjoy your bitters and beer.
 
So you think that this setup is fine?
 

Similar threads

Not sure where to start in a large logistics problem
  • · Replies 9 ·
Replies
9
Views
2K
Pascal's Principle? Are my solutions correct?
  • · Replies 2 ·
Replies
2
Views
3K
How many steel profiles do I need to support a workshop roof in Santiago, Chile?
  • · Replies 3 ·
Replies
3
Views
2K
Simple Machines Revisited + more - making 2.5 ton lift
  • · Replies 2 ·
Replies
2
Views
2K
Need Help with Newton's Laws Problems?
  • · Replies 2 ·
Replies
2
Views
8K
Calculating Force/Mass Using Pascal's Principle for Baby-Lifting Car
  • · Replies 4 ·
Replies
4
Views
3K