Negating a statement, quick check.

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SUMMARY

The discussion focuses on the negation of a set defined as S = {(x, y) ∈ ℝ | (x, y ∈ ℚ) or (x, y ∉ ℚ)}. The correct negation results in T = {(x, y) ∈ ℝ | (x ∈ ℚ or y ∈ ℚ) and (x ∉ ℚ or y ∉ ℚ)}, indicating that one coordinate must be rational while the other must be irrational. This conclusion is affirmed as correct based on elementary rules of logic. Additionally, the user expresses challenges with LaTeX formatting for set complements and brackets.

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malicx
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Homework Statement


So, I have a set
S = (x, y) \in \mathbb{R} | (x and y \in \mathbb{Q}) or (x and y \notin \mathbb{Q})

I want to find
T = \mathbb{R} minus S

so I am negating this and get


T = (x, y) \in \mathbb{R} | (x or y \in \mathbb{Q}) and (x or y \notin \mathbb{Q})

which really just means that one coordinate must be rational, and the other must be irrational. Is this correct?

Thanks. I also seem to be having problems in latex getting the set complement R\S and brackets around my sets working, so sorry about that.
 
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This seems ok!
 
yes this is correct, it follows from elementary rules of logic
 

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