Net Force Produced By Currents In Wire And Square Loop

[JennV]

Homework Statement

A long, straight wire carries a current of 14A. Next to the wire is a square loop with sides 1.0m in length, as shown in the figure. The loop carries a current of 2.5A in the direction indicated.

http://img69.imageshack.us/i/walker2260.jpg/

Calculate the magnitude of the net force acting on the loop.

Homework Equations

B = Uo*I / 2*pi*r
F= I*L*B

The Attempt at a Solution

B = (4pi*10^-7)(14A) / (2pi(0.2m)) = 1.4*10^-5 T
B = (4pi*10^-7)(14A) / (2pi(1.2m)) = 2.33*10^-6 T

B = (1.4*10^-5 T)-(2.33*10^-6 T) = 1.16666*10^-5

Fnet = (2.5A)(1.0m)(1.16666*10^-5 T) = 2.916666*10^-5 N

Did I do this right? I only have one attempt left, so I'm worried that I will get it wrong.
Thank you in advance.

 

[gabbyl]

This is from a long time ago but for anyone else wondering the answer is correct. I know this because I just submitted it as an answer for a homework assignment (Mastering Physics) and I got it right.