Neuronal Dynamics Passive membrane equation

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SUMMARY

The discussion focuses on solving the differential equation of the passive membrane model, specifically the equation T_m dv/dt = -v. The integration process leads to the solution v = -RI_0 e^{-t/T_m}, which is derived from the initial condition v = -RI_0 when t = 0. The final expression for the membrane potential u is u = u_rest + RI_0(1 - e^{-t/T_m}). This solution is crucial for understanding neuronal dynamics in the context of passive membrane behavior.

PREREQUISITES
  • Understanding of differential equations and integration techniques
  • Familiarity with neuronal dynamics and passive membrane models
  • Knowledge of the constants T_m (membrane time constant) and R (resistance)
  • Basic concepts of electrical potentials in biological systems
NEXT STEPS
  • Study the derivation of the passive membrane equation in detail
  • Explore the implications of the time constant T_m in neuronal signaling
  • Learn about the role of resistance R in neuronal membrane models
  • Investigate numerical methods for simulating neuronal dynamics
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Neuroscientists, biophysicists, and students studying neuronal dynamics or mathematical modeling of biological systems will benefit from this discussion.

winterdrops
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Hi guys,

I am able to solve dif equation of passive membrane model. But later, author says following instructions to integrate first model. Even though I can solve the dif equation of model, I couldn't achieve the solution.

Could you help me pls. Best regards.
 

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Let $v = u - u_{\text{rest}}-RI_0$. Since $I(t) = I_0$, the equation becomes $T_m\, dv/dt = -v$, or $dv/v = -dt/T_m$. Integrating both sides, we obtain $\ln|v| = -t/T_m + C$ where $C$ is a constant. Thus $v = Ae^{-t/T_m}$ where $A$ is a constant. Since $v = -RI_0$ when $t = 0$, then $A = -RI_0$. Hence $v = -RI_0 e^{-t/T_m}$, or, $$u = u_{\text{rest}} + RI_0 - RI_0 e^{-t/T_m} = u_{\text{rest}} + RI_0(1 - e^{-t/T_m})$$
 

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