fluidistic said:
Ok thank you very much atyy, I'm going to have a close look as soon as I can, on all these ressources. It's very nice to know that my book then is not that outdated on the subject.
Meanwhile, I have some questions and doubts. In my book it basically states that the potential of the soma has the form ##\frac{dV}{dt}=h(V)+e(V)i(t)## where i(t) is an input signal, e(V) describes the effect of the input signal (from what I understood in wikipedia, this function would be the synaptic weight?) and h(V) describes the decay of the potential when there's no input signal.
Has this method a name?
The notation is a bit different from what I'm used to, so here's my guess.
For a simple model I usually write CdV/dt = GR(ER-V) + GS(t)(ES-V). This is a model with no voltage dependent conductances, so no spikes, just passive membrane receiving synaptic input.
V = membrane potential
t = time
C = membrane capacitance
GR = resting membrane conductance
ER = resting membrane potential
GS = synaptic conductance
ES = synaptic reversal potential
ES-V is often called the "synaptic driving force"
If I rearrange I get dV/dt = (1/C)[-GR.V + GR.ER +GS(t)(ES-V)]
If I conpare with the equation in your book, I get
h(V) = -GR.V/C
m = GR.ER/C
i(t) = GS(t)/C
e(V) = (ES-V)/C
So i(t) would be the synaptic conductance and e(V) would be the the synaptic driving force. (divided by the membrane capacitance).
fluidistic said:
Then the book made some simplifications, like that the mean value of the function i(t) would be worth m, h(V) would take the form ##-V/\tau## where tau is the rate of decay constant. Also it assumed that the change in the potential due to the arriving signal is indepent on the current value of the potential and is proportional to the input.
Then the potential takes the form ##\frac{dV}{dt}=-\frac{V}{\tau} +m +\sigma F(t)## where F(t) is a white noise function (worth exactly ##\frac{[i(t)-m]}{\sigma}##) with mean 0 and both m and sigma are positive constants. I've solved the equation when the noise is worth 0 and it's an exponential decreasing function (##V(t)=Ae^{-t/\tau}+m\tau##). So if I understand well, this V(t) describes the potential of the soma right after having fired? It has a high initial value and then exponentially decreases toward the mean value of the white noise multiplied by tau.
Later the book states that m>0 is more realisitic than m<0, I can understanding that. But it also states that in the limit when tau tends to infinity (not realistic), this is equivalent to the case of when the time taken for the potential to reach its resting value (m times tau I guess) is much slower than the time between 2 firings.
So if I understand well, a huge value for tau would mean that the neuron fires extremely fast?
How unrealistic is this? Because this makes the math slightly simpler if I take tau that tends to infinity (but still drastically complicated), for a stochastic analysis.
With these simplifications, the model seems to be just the same as the simple model I wrote above, so it would have no action potentials, and be just a passive membrane. The solution you wrote is just passive decay to resting membrane potential from an initial condtion in which the membrane had been perturbed from from rest.