Newtonian Mechanics: simultaneous equations

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Homework Help Overview

The problem involves two blocks connected by a cord over a pulley, with one block sliding on a frictionless surface and the other hanging. The objective is to find the accelerations of both blocks and the tension in the cord, using Newtonian mechanics principles.

Discussion Character

  • Mathematical reasoning, Problem interpretation, Assumption checking

Approaches and Questions Raised

  • The original poster expresses difficulty with the mathematical aspect of solving simultaneous equations derived from the forces acting on both blocks. Some participants suggest clarifying the use of variables and how to substitute one equation into another to find the acceleration.

Discussion Status

Participants are actively engaging with the equations and attempting to derive the relationship between the variables. One participant reports successfully manipulating the equations to find an expression for acceleration, while another confirms the correctness of this approach. However, there is no explicit consensus on the final solution.

Contextual Notes

The discussion highlights the importance of correctly identifying and using variables in the equations, as well as the challenges posed by simultaneous equations in this context.

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Homework Statement


Figure 5-12 shows a block S (the sliding block) with mass
M 3.3 kg. The block is free to move along a horizontal
frictionless surface and connected, by a cord that wraps over
a frictionless pulley, to a second block H (the hanging
block), with mass m 2.1 kg. The cord and pulley have neg-
ligible masses compared to the blocks (they are “massless”).
The hanging block H falls as the sliding block S accelerates
to the right. Find (a) the acceleration of block S, (b) the ac-
celeration of block H, and (c) the tension in the cord.

Homework Equations


Block S:
Tx=ma (on the X axis)

Block H:

T-mg=-ma (y axis)

The Attempt at a Solution


I understand the theory and question, my problem lies with my math skills. Because of the two unknown variables you can solve them simultaneously, however the sample problem assumes I remember how to do it!

I want to understand how you can mathematically go from the two equations on top to a=(m/M+m)g on the y axis.
Thank you for the help!
 
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To avoid confusion you need to use M and m in your relevant equations.
Also note that what you've called Tx is equal to what you've called T (and of course a is the same also) so you can plug one equation into the other and solve for a.
 
After playing around with the equations I got it. Thanks for the help! I should pay more attention to the variables. :D

I ended up going like:
T-mg=-ma -----> T=-ma+mg
T=Ma -----> (plug in eqquation number 1) -ma+mg=Ma ----->Ma+ma=mg------->a(M+m)=mg----->a=mg/M+m

Would this set up be okay?
 
That looks right. Good work.
 

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