- #1

- 6

- 0

my way:

T1=24.5N θ=30

T2=42.7N θ= -60

m=?

m=Fnet/a

the ans should be (m=5.017 Kg)

- Thread starter shamma
- Start date

- #1

- 6

- 0

my way:

T1=24.5N θ=30

T2=42.7N θ= -60

m=?

m=Fnet/a

the ans should be (m=5.017 Kg)

- #2

- 993

- 13

How many forces act on the mass?

- #3

- 6

- 0

3 forces

Fg and 2 tension forces

Fg and 2 tension forces

- #4

- 993

- 13

Now find the vertical components of the two tensions.

- #5

- 6

- 0

T1: 24.5 sin 60=21.21N

T2: 42.7 sin 30=21.35N

T2: 42.7 sin 30=21.35N

- #6

- 993

- 13

If you draw a diagram you will notice that the above are the HORIZONTAL components.T1: 24.5 sin 60=21.21N

T2: 42.7 sin 30=21.35N

(Incidentally, the horizontal components must be equal in magnitude)

- #7

- 6

- 0

yes, your right.

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