Newton's cradle: Glue balls together

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SUMMARY

The discussion centers on the physics of Newton's cradle, specifically the implications of gluing the last two balls together or replacing them with a single ball of double the mass. It is established that if one ball is pulled away and released, the conservation of momentum and energy would be violated if two balls were to bounce off while the others remained stationary. The proposed solution indicates that when the last two balls are glued, the first ball rebounds with a velocity of -1/3 v, while the glued balls move off with a velocity of 2/3 v, satisfying conservation laws under these conditions.

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  • Understanding of Newton's laws of motion
  • Familiarity with conservation of momentum and energy
  • Basic knowledge of elasticity in collisions
  • Experience with practical physics experiments, such as using coins on a smooth surface
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greypilgrim
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Hi.

Assuming only one ball is pulled away and let go, it's fairly easy to show that momentum and/or energy conservation would be violated if this made two balls to bounce off on the other side (if the other ones remain still).

So what happens if we glue the last to balls together or replace them with one ball twice the mass?
 
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The physics of Newtons cradle is a lot more complicated than this.

My guess is the ball you pull away and let go bounces back (in addition to the heavy one moving off).

Practice with a row of coins on a smooth table.
 
I know that conservation of energy and momentum allow for more than one solution and you need to take into account the elasticity of the balls to find which solution is realized. So I wonder what happens if we forbid this solution, i.e. by glueing the last two balls together.

If the first ball has velocity v, conservation of energy and momentum are satisfied when the first ball bounces back with -1/3 v and the last two balls bounce off with 2/3 v. I guess this solution will be realized instead.
 

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