Newtons third law/law of gravitation

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SUMMARY

The discussion centers on the gravitational force acting on a comet as it moves ten times farther from Earth, applying Newton's law of gravitation. The gravitational force is calculated using the formula Fgrav = GM1M2/r², demonstrating that the force is inversely proportional to the square of the distance. As the distance increases to ten times, the gravitational force decreases to one hundredth of its original size, confirming that the correct answer is option d) One hundredth as large as before. Additionally, the conversation clarifies the implications of Newton's third law, emphasizing that forces between two masses are equal and opposite.

PREREQUISITES
  • Understanding of Newton's law of gravitation
  • Familiarity with the equation Fgrav = GM1M2/r²
  • Concept of inverse proportionality in physics
  • Basic knowledge of Newton's third law of motion
NEXT STEPS
  • Study the implications of gravitational force in varying distances
  • Explore examples of Newton's third law in real-world applications
  • Learn about gravitational interactions in multi-body systems
  • Investigate the effects of mass on gravitational attraction
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Students studying physics, educators teaching gravitational concepts, and anyone interested in understanding the principles of Newton's laws and their applications in celestial mechanics.

vipson231
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Homework Statement



A comet is affected by a gravitational force due to the presence of the Earth. Later, the comet is ten times farther from the Earth. What is the size of the new gravitational force acting on the comet?

a) One hundred times larger than before.
b) Ten times larger than before.
c) One tenth as large as before.
d) One hundredth as large as before.

Based on what I'm given, gravitational force is inversely proportional to the square of the distance (r). So if the distance is 10, don't you just square 10 to get 100 times larger? I'm kinda stuck between a or d I don't know why =p

Also for the question on the attachment (sorry for the horrendous quality) I can't seem to narrow down the choices given that I don't understand what each choice means. All I know is that Newtons third law is equal and opposite force but I can't find a corresponding answer that upholds the statement.


Homework Equations


Fgrav= GM1M2/r^2
 

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vipson231 said:
gravitational force is inversely proportional to the square of the distance (r).
Do you understand what inversely proportional proportional means? If y is inversely proportional to x then y is proportional to 1/x. So if you double x, what happens to y?
on the attachment (sorry for the horrendous quality) I can't seem to narrow down the choices given that I don't understand what each choice means.
The equation you quote tells you how strong an attractive force a mass m1 will feel from a mass m2, right?
The first option observes that if you swap m1 and m2 in the equation you get the same answer. Do you agree with that? What does that imply about the force each mass experiences? Is that what Newton's 3rd law says?
The second option says the larger mass feels a stronger pull, but because it has more mass that cancels out that the pull is stronger. Do you agree with the first part of that? If so, do you agree with the second part? If so, is that what Newton's 3rd law is saying?
The third option is the same as the second except that it claims the smaller mass feels the stronger pull.
The fourth option says that if the masses are different then the two masses will feel different forces.
 
Thanks for clarifying all the answer choices. Crystal clear to me now =]
 

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