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kaliprasad
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show that the equation $4xy - x - y = z^2$ has no positive integer solution
individ said:I decided in the General form:
It's pretty old equations that are solved by Euler.
the equation:
\(\displaystyle aXY+X+Y=Z^2\)
If we use the solutions of Pell's equation: \(\displaystyle p^2-acs^2=\pm1\)
Solutions can be written:
\(\displaystyle X=\pm(c+1)s^2\)
\(\displaystyle Y=\pm(c+1)cs^2\)
\(\displaystyle Z=ps(c+1)\)
\(\displaystyle c\) - We ask ourselves. While the formula and can be written differently.
Equation: \(\displaystyle p^2-4cs^2=-1\) has no solutions.
Because : \(\displaystyle \frac{p^2+1}{4}\) may not be an integer.
kaliprasad said:show that the equation $4xy - x - y = z^2$ has no positive integer solution
individ said:Leave the rest of modular arithmetic.
Should equation to solve.
You generally solutions not, and they are when the number is negative.
I asked about the decision not such equation, and such?
\(\displaystyle aXY-X-Y=Z^2\)
The equation "4xy - x - y = z^2" is called a Diophantine equation, named after the ancient Greek mathematician Diophantus who studied these types of equations.
No, there are no positive integer solutions for this equation. This has been proven through various mathematical methods, including modular arithmetic and number theory.
The main reason why there are no positive integer solutions for this equation is because it is a type of equation known as a "congruent number problem". These types of equations are notoriously difficult to solve and have been an area of study for mathematicians for centuries.
Yes, there are infinitely many negative integer solutions for this equation. Some examples include (-1, 1, 0), (-2, 1, 1), and (-3, 2, 3). However, there are no positive integer solutions for this equation.
Yes, this equation can be solved for non-integer values. In fact, there are infinite real number solutions for this equation. However, when the requirement for solutions to be positive integers is added, there are no solutions.