Noble Gas Configuration for Uranium: Tips and Tricks to Complete [Rn] 7s2

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SUMMARY

The noble gas configuration for uranium is completed as [Rn] 7s2 6d1 5f3. This configuration reflects the stability preference of electron orbitals, where 5f is filled after 6d. The discussion highlights the importance of understanding the order of filling in electron configurations, particularly in transition metals and actinides. The user initially misordered the orbitals but corrected it by recognizing that 5f follows 6d in uranium's configuration.

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Could someone please help me finish the nobel gas configuration for uranium? I get as far as [Rn] 7s2, but I can't figure out what goes next.
 
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What is the reason for this structure? I assume the 5F3 is more stable than 5f4, kind off like the half filled 3d5 taking preference.

On a related note I was looking here http://www.chemguide.co.uk/atoms/properties/ionstruct.html#top, and intuitively I'd though of thought when Fe beomces Fe3+ that a 3d atom would be lost before the 4s atom since that 3d54s2, is more stable than 3d64d1?

note: been a while since I did any chemistry.
 
Ok I see what my mistake was...I had the first part right, but then I kept putting 5f before 6d. In this case, 5f goes afterward, so the configuration is actually [Rn] 7s2 6d1 5f3.

Thanks for the help. :)
 

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