Non-elastic collision without outside influence

  • Thread starter Thread starter nhmockus
  • Start date Start date
  • Tags Tags
    Collision Outside
Click For Summary
SUMMARY

The discussion centers on a head-on elastic collision involving two balls, where ball A rebounds with a speed equal to one-fourth of its original speed after colliding with ball B, which is initially at rest. The relevant equation for this scenario is v(1) = u(1) * (m(1) - m(2)) / (m(1) + m(2)). The user attempts to solve for the mass of ball B by substituting v(1) with 1/4 u(1) but struggles to find a solution that satisfies the equation. The importance of considering the direction of velocities in collisions is also highlighted.

PREREQUISITES
  • Understanding of elastic collision principles
  • Familiarity with momentum conservation laws
  • Basic knowledge of algebraic manipulation
  • Concept of vector quantities in physics
NEXT STEPS
  • Study the conservation of momentum in elastic collisions
  • Learn how to apply the equations of motion in collision scenarios
  • Explore examples of one-dimensional elastic collisions
  • Investigate the role of mass ratios in collision outcomes
USEFUL FOR

Students of physics, educators teaching mechanics, and anyone interested in understanding the principles of elastic collisions and momentum conservation.

nhmockus
Messages
5
Reaction score
0
A ball A of mass makes a head-on elastic collision with a second ball B (at rest) and rebounds in the opposite direction with a speed equal to one-fourth its original speed. What is the mass of the second ball B?

I think an appropriate equation for this is v(1)= u(1)*(m(1)-m(2))/(m(1)+m(2))

I tried solving this by changing v(1) to 1/4 u(1) and then trying to find something that makes that long equation next to u(1) equal 1/4 but I can't seem to find anything
 
Physics news on Phys.org
nhmockus said:
A ball A of mass makes a head-on elastic collision with a second ball B (at rest) and rebounds in the opposite direction with a speed equal to one-fourth its original speed. What is the mass of the second ball B?

I think an appropriate equation for this is v(1)= u(1)*(m(1)-m(2))/(m(1)+m(2))

I tried solving this by changing v(1) to 1/4 u(1) and then trying to find something that makes that long equation next to u(1) equal 1/4 but I can't seem to find anything

Hi nhmockus, welcome to Physics Forums.

Remember that velocities have directions.
 

Similar threads

  • · Replies 15 ·
Replies
15
Views
4K
  • · Replies 13 ·
Replies
13
Views
1K
Replies
20
Views
3K
  • · Replies 2 ·
Replies
2
Views
3K
Replies
10
Views
3K
Replies
1
Views
2K
  • · Replies 10 ·
Replies
10
Views
3K
Replies
34
Views
3K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 16 ·
Replies
16
Views
4K