- #1

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y"+3y'+2y= sin x

y(0)=0

y'(0)=1

Evaluate y(0.1)

Thanks!

- Thread starter teddy_boo
- Start date

- #1

- 8

- 0

y"+3y'+2y= sin x

y(0)=0

y'(0)=1

Evaluate y(0.1)

Thanks!

- #2

HallsofIvy

Science Advisor

Homework Helper

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It would be better if you what you understand about this problem and where you have trouble. What have you tried?

(I suppose it would be tacky of me to suggest that this looks like a homework problem. You wouldn't do that, would you?)

- #3

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You are aware this can be solved analytically, yes? Just making sure.

- #4

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- #5

HallsofIvy

Science Advisor

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- #6

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∑_(i=2)^∞▒〖i(i-1) a_i x^(i-2)+3∑_(i=1)^∞▒〖ia_i x^(i-1)+2∑_(i=0)^∞▒〖a_i x^i=∑_(i=0)^∞▒(〖(-1)〗^i x^(2i+1))/(2i+1)!〗〗〗

- #7

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(2a_2+6a_3 x+12a_4 x^2+⋯)+(3a_1+6a_2 x+9a_3 x^2+⋯)+(2a_0+2a_1 x+2a_2 x^2+⋯)=x-x^3/3!+x^5/5!+⋯

- #8

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After expansion, I don't know how to factor x^3 and x^5 terms.

- #9

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