# (Non-)mixing of K vector bosons

1. Dec 14, 2011

### Smithf

Why dont the vector bosons K(0*) and K-bar(0*) mix the way the pseudo-scalar bosons,
K(0) and K-bar(0) do?

2. Dec 14, 2011

Staff Emeritus

3. Dec 14, 2011

### Smithf

I dont know how to do the suggested calculation -- I was expecting some sort of selection rule to apply

4. Dec 14, 2011

### Smithf

Is the idea that the K* just decays too quickly into Kπ by a strong interaction?

5. Dec 14, 2011

Staff Emeritus
Bingo.

And you do know how to do the calculation. Look up both numbers and divide.

I $k^0-\bar{k^0}$ mixing and gauge boson propagator Jan 23, 2017