Non Uniform Circular Motion w/ Calculus and Vectors

In summary, the train is slowing down from 90 km/hr to 50 km/hr while rounding a sharp horizontal turn with a radius of 150 m. The acceleration at the moment the train reaches 50 km/hr can be found by calculating the centripetal acceleration and the tangential acceleration, using pythagoras and trigonometry to combine them. The speed of the train should be converted from km/hr to m/s for accurate calculations. It is important to note that the train continues to slow down at the same rate during this time.
  • #1
rue7
1
0
Hello! I have a problem which is solvable using simpler methods, but I'm trying to use it as a bridge to understanding how to do these problems in a more rigorous setting.

Homework Statement


A train slows down as it rounds a sharp horizontal turn, slowing from 90 km/hr to 50 km/hr in the 15 s that it takes to round the bend. The radius of the curve is 150 m. Compute the acceleration at the moment the train speed reaches 50 km/hr. Assume it continues to slow down at this time at the same rate.

Homework Equations





The Attempt at a Solution



First Attempt

My first attempt involved starting with a position vector

r(t) = acos(t)i + asin(t)j

where a = the radius of the curve.

However, when I took the derivative of this my attempt quickly crumbled, because:

r'(t) = v(t) = -asin(t)i + acos(t)j

in which:

|v(t)| = [itex]\sqrt{a^{2}sin^{2}(t) + a^{2}cos^{2}(t)} [/itex] = a

The magnitude of the velocity vector = a at all times t? I knew this couldn't be true so I made my second attempt.

Second Attempt

This time I started with a tangent acceleration + radial acceleration vector:

a(t) = a[itex]_{t}[/itex] T + a[itex]_{n}[/itex][itex] \kappa[/itex] N

where T is the tangent unit vector, N is the normal (or radial) unit vector and [itex]\kappa[/itex] is the curvature of the circle.

My failure here is either a lack of understanding in how to present the circular motion's acceleration or in my own ability to manipulate that vector back into a velocity vector and as well as a position vector.

Additional note:

As I said in the beginning, I know this problem is solvable by using formulas already derived using vectors and Calculus. In fact, this problem was taken from a book for a course that only requires Calculus 1. However, when I discovered how to solve Two-Dimensional (not rotational) Motion problems using derivatives and integrals rather than the "suvat" Equations of Motion beginning Physics students are taught to memorize, I immediately became curious how this can be done with Circular Motion Problems.


Many thanks if you read this far. Infinite thanks in advance for anyone who chooses to help me understand.
 
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  • #2
rue7 said:
Hello! I have a problem which is solvable using simpler methods, but I'm trying to use it as a bridge to understanding how to do these problems in a more rigorous setting.

Homework Statement


A train slows down as it rounds a sharp horizontal turn, slowing from 90 km/hr to 50 km/hr in the 15 s that it takes to round the bend. The radius of the curve is 150 m. Compute the acceleration at the moment the train speed reaches 50 km/hr. Assume it continues to slow down at this time at the same rate.

Homework Equations





The Attempt at a Solution



First Attempt

My first attempt involved starting with a position vector

r(t) = acos(t)i + asin(t)j

where a = the radius of the curve.

However, when I took the derivative of this my attempt quickly crumbled, because:

r'(t) = v(t) = -asin(t)i + acos(t)j

in which:

|v(t)| = [itex]\sqrt{a^{2}sin^{2}(t) + a^{2}cos^{2}(t)} [/itex] = a

The magnitude of the velocity vector = a at all times t? I knew this couldn't be true so I made my second attempt.

Second Attempt

This time I started with a tangent acceleration + radial acceleration vector:

a(t) = a[itex]_{t}[/itex] T + a[itex]_{n}[/itex][itex] \kappa[/itex] N

where T is the tangent unit vector, N is the normal (or radial) unit vector and [itex]\kappa[/itex] is the curvature of the circle.

My failure here is either a lack of understanding in how to present the circular motion's acceleration or in my own ability to manipulate that vector back into a velocity vector and as well as a position vector.

Additional note:

As I said in the beginning, I know this problem is solvable by using formulas already derived using vectors and Calculus. In fact, this problem was taken from a book for a course that only requires Calculus 1. However, when I discovered how to solve Two-Dimensional (not rotational) Motion problems using derivatives and integrals rather than the "suvat" Equations of Motion beginning Physics students are taught to memorize, I immediately became curious how this can be done with Circular Motion Problems.


Many thanks if you read this far. Infinite thanks in advance for anyone who chooses to help me understand.

The net acceleration here has two components. The centripetal acceleration, due to the fact that is is traveling at 50 km/h in a circular path of radius 150m, and a "circumferential" or tangential component due to the fact it is slowing down. It is slowing down at a rate that will cause its speed to reduce from 90 km/h to 50 km/h in 15 seconds. Calculate each component, then combine them - making use of pythagorus and trignometry as appropriate.

During you calculations you will need to change those km/h speeds to m/s.

btw the bit "Assume it continues to slow down at this time at the same rate." is there lest you think that the train, having slowed to 50km/h, then continued at that constant speed - which would have made the tangential acceleration impossible to estimate.
 

FAQ: Non Uniform Circular Motion w/ Calculus and Vectors

What is non-uniform circular motion?

Non-uniform circular motion is when an object moves in a circular path at varying speeds, meaning its velocity is not constant. This type of motion can be described using calculus and vectors.

How can calculus be used to describe non-uniform circular motion?

Calculus can be used to describe non-uniform circular motion by analyzing the rate of change of an object's position, velocity, and acceleration over time. This involves using derivatives and integrals to calculate the object's instantaneous speed and acceleration at any given point.

What is the role of vectors in non-uniform circular motion?

Vectors play a crucial role in non-uniform circular motion as they allow us to represent the direction and magnitude of an object's velocity and acceleration. This is important because, in non-uniform circular motion, the direction of an object's velocity and acceleration is constantly changing.

How is centripetal acceleration calculated in non-uniform circular motion?

Centripetal acceleration in non-uniform circular motion can be calculated using the equation a = v^2/r, where a is the acceleration, v is the velocity, and r is the radius of the circular path. This formula can be derived using calculus and the concept of instantaneous velocity.

Can non-uniform circular motion occur in real-life scenarios?

Yes, non-uniform circular motion can occur in various real-life scenarios such as a car going around a curved road, a rollercoaster, or a satellite orbiting around a planet. In these situations, the object's velocity and acceleration are constantly changing, making it an example of non-uniform circular motion.

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